我有以下列表播放器。
+-----------+------------+------------+
| player_id | mission_id | reg_time |
+-----------+------------+------------+
| 1 | 1 | 1508392600 |
| 1 | 2 | 1508392800 |
| 1 | 3 | 1508392900 |
| 1 | 4 | 1508392822 |
| 2 | 1 | 1508392500 |
| 2 | 2 | 1508392600 |
| 2 | 3 | 1508392900 |
| 3 | 1 | 1508392600 |
| 3 | 2 | 1508392600 |
| 3 | 3 | 1508392900 |
| 3 | 4 | 1508392900 |
| 4 | 1 | 1508392600 |
| 4 | 3 | 1508392900 |
+-----------+------------+------------+
我希望所有的player_id都有
mission_id = 1,2和reg_time< = 1508392800和
mission_id = 3,4和reg_time> 1508392800如下
+-----------+------------+------------+
| player_id | mission_id | reg_time |
+-----------+------------+------------+
| 1 | 1 | 1508392600 |
| 1 | 2 | 1508392800 |
| 1 | 3 | 1508392900 |
| 1 | 4 | 1508392822 |
| 3 | 1 | 1508392600 |
| 3 | 2 | 1508392600 |
| 3 | 3 | 1508392900 |
| 3 | 4 | 1508392900 |
+-----------+------------+------------+
我如何通过mysql做到?
答案 0 :(得分:1)
您可以尝试使用此代码来获得所需的结果。
SELECT *
from `players` AS p
where (exists (select *
from `players` as p1
where p1.player_id = p.player_id
AND p1.mission_id = 1 AND p1.reg_time <= 1508392800 )
AND exists (select *
from `players` as p2
where p2.player_id = p.player_id
AND p2.mission_id = 2 AND p2.reg_time <= 1508392800))
AND (exists (select *
from `players` as p3
where p3.player_id = p.player_id
AND p3.mission_id = 3 AND p3.reg_time > 1508392800)
AND exists (select *
from `players` as p4
where p4.player_id = p.player_id
AND p4.mission_id = 4 AND p4.reg_time > 1508392800))