Question

我在数据库中有一些记录，我将它们作为。

  def get_all_records_for_sim(sim_number) do
    SimLogs
    |> where(number: ^sim_number)
    |> order_by(asc: :datetime)
    |> Repo.all
    |> IO.inspect
  end

因此，我得到了这种数据，

 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-12 10:39:00.839670], id: 795, name: "User 6 Sim",
  number: "0860100421", volume_used: "0.00 MB"},
 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-12 11:02:20.296758], id: 815, name: "User 6 Sim",
  number: "0860100421", volume_used: "0.00 MB"},
 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-13 05:30:25.800565], id: 837, name: "User 6 Sim",
  number: "0860100421", volume_used: "0.00 MB"},
 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-16 05:24:04.536224], id: 859, name: "User 6 Sim",
  number: "0860100421", volume_used: "0.00 MB"},
 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-16 12:28:21.565377], id: 881, name: "User 6 Sim",
  number: "0860100421", volume_used: "43.09 MB"},
 %EdgeCommander.ThreeScraper.SimLogs{__meta__: #Ecto.Schema.Metadata<:loaded, "sim_logs">,
  addon: "60GB Broadband", allowance: "61,440.00 MB",
  datetime: ~N[2017-10-17 05:03:49.866221], id: 903, name: "User 6 Sim",
  number: "0860100421", volume_used: "43.09 MB"}]

有很多副本来自它，但不完全相同但是如果你看DateTime，则日期的第一部分与2017-10-12和2017-10-16相同，在上面的示例中，我正在处理该数据以进一步创建图表行

chartjs_data =
  sim_number
  |> get_all_records_for_sim()
  |> Enum.map(fn(one_record) ->
    {current_in_number, _} = one_record |> get_volume_used() |> String.replace(",", "") |> Float.parse()
    {allowance_in_number, _} = one_record |> get_allowance() |> String.replace(",", "") |> Float.parse()

    %{
      datetime: "#{shift_datetime(one_record.datetime)}",
      percentage_used: (current_in_number / allowance_in_number * 100) |> Float.round(3)
    }
  end)

导致这样的对象{percentage_used: 0, datetime: "2017-10-10 05:03:49"}的数组，我的问题是，我想合并相同的日期，例如，如果有7个2017-10-12的记录，那么将它们设为一个，并且因为对象的另一半基于volume_used（ecto结果查询），所以得到所有这7个记录volume_used的平均值并将其设为1并将对象创建为{percentage_used: MEAN_OF_ALL_7_RECORDS, datetime: "2017-10-12"} ..

有多种方法可以做到这一点，但我正在寻找它是否可能在ecto，或在服务器端只能以任何有效的方式？任何帮助都会很明显。

更新：或者可能在jquery中可以处理这些数据，

[{percentage_used: 0, datetime: "2017-10-10 05:03:49"}
{percentage_used: 0, datetime: "2017-10-10 17:13:38"}
{percentage_used: 0, datetime: "2017-10-11 04:39:32"}
{percentage_used: 0, datetime: "2017-10-11 12:50:42"}
{percentage_used: 0, datetime: "2017-10-12 06:31:22"}
{percentage_used: 0, datetime: "2017-10-12 09:21:08"}
{percentage_used: 0, datetime: "2017-10-12 09:34:33"}
{percentage_used: 0, datetime: "2017-10-12 10:17:00"}
{percentage_used: 0, datetime: "2017-10-12 10:39:00"}
{percentage_used: 0, datetime: "2017-10-12 11:02:20"}]

并制作类似

的内容

[{percentage_used: 0, datetime: "2017-10-10"}
{percentage_used: 0, datetime: "2017-10-11"}
{percentage_used: 0, datetime: "2017-10-11"}]

任何解决方案都是值得的。感谢

Answer 1

您可以在查询中使用DISTINCT ON date_trunc('day', datetime)每天只从数据库返回一条记录：

SimLogs
|> where(number: ^sim_number)
|> distinct([s], fragment("date_trunc('day', ?)", s.datetime))
|> order_by(asc: :datetime)
|> Repo.all

要获取每天的最后一条记录，您可以修改order_by：

|> order_by([s], [asc: fragment("date_trunc('day', ?)", s.datetime), desc: s.datetime])

跳过并合并类似的数据ecto elixir

1 个答案: