Question

pdb的display命令似乎只在分配整个变量时显示一个表达式。

pass
foo = [1, 2, 3]
foo[0] = 8
foo.append(7)
pass

使用python3 -m pdb bar.py运行上述代码然后输入display foo时获得的输出是：

> bar.py(2)<module>()
-> foo = [1, 2, 3]
(Pdb) display foo
display foo: ** raised NameError: name 'foo' is not defined **
(Pdb) n
> bar.py(3)<module>()
-> foo[0] = 8
display foo: [1, 2, 3]  [old: ** raised NameError: name 'foo' is not defined **]
(Pdb) 
> bar.py(4)<module>()
-> foo.append(7)
(Pdb) 
> bar.py(5)<module>()
-> pass
(Pdb) foo
[8, 2, 3, 7]
(Pdb)

需要NameError和显示的第一个输出。但是，当第一个项目被更改或者我们追加7时，显示器似乎没有发现foo已更改。

有没有办法告诉pdb列出这些更改？似乎display str(foo)完成了这项工作，但我想知道是否有更好的解决方案。

Answer 1

是的，跟踪这些更改的方法是改为'p'命令。见这个例子

> /home/maksim/Projects/Python/basic/test.py(2)<module>()
-> foo = [1, 2, 3]
(Pdb) s;;l;;p foo
> /home/maksim/Projects/Python/basic/test.py(3)<module>()
-> foo[0] = 8
  1     pass
  2     foo = [1, 2, 3]
  3  -> foo[0] = 8
  4     foo.append(7)
  5     pass
  6     
  7     
  8     
[EOF]
[1, 2, 3]
(Pdb) s;;l;;p foo
> /home/maksim/Projects/Python/basic/test.py(4)<module>()
-> foo.append(7)
  1     pass
  2     foo = [1, 2, 3]
  3     foo[0] = 8
  4  -> foo.append(7)
  5     pass
  6     
  7     
  8     
[EOF]
[8, 2, 3]
(Pdb) s;;l;;p foo
> /home/maksim/Projects/Python/basic/test.py(5)<module>()
-> pass
  1     pass
  2     foo = [1, 2, 3]
  3     foo[0] = 8
  4     foo.append(7)
  5  -> pass
  6     
  7     
  8     
[EOF]
[8, 2, 3, 7]
(Pdb) s;;l;;p foo
--Return--
> /home/maksim/Projects/Python/basic/test.py(5)<module>()->None
-> pass
  1     pass
  2     foo = [1, 2, 3]
  3     foo[0] = 8
  4     foo.append(7)
  5  -> pass
  6     
  7     
  8     
[EOF]
[8, 2, 3, 7]
(Pdb)

python3 pdb显示列表

1 个答案: