Question

我尝试使用phpmyadmin执行CRUD操作当我选择编辑选项后，我得到错误，我尝试但没有得到它

我在编辑操作中遇到以下错误

注意：未定义的索引：在C：\ wamp \ www \ projects \ edit.php中编辑   3

（！）注意：未定义的变量：C：\ wamp \ www \ projects \ edit.php中的id   第23行调用堆栈#TimeMemoryFunctionLocation 10.0010252672 {main}（   ）.. \ edit.php：0＆＃34;方法=＆＃34;后＆＃34;＆GT; name =
password =
email =


注意：未定义索引：C：\ wamp \ www \ projects \ edit.php中的edit_form   第39行

-- Table structure for table `user`

警告：无法修改标头信息 - 已发送的标头（输出从C：\ wamp \ www \ projects \ edit.php：26开始）第46行的C：\ wamp \ www \ projects \ edit.php

CREATE TABLE IF NOT EXISTS `user` (
  `userid` varchar(50) NOT NULL,
  `name` varchar(50) NOT NULL,
  `email` varchar(100) NOT NULL,
  `pass` varchar(50) NOT NULL,
  `timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
  `id` int(11) NOT NULL AUTO_INCREMENT,
  PRIMARY KEY (`id`),
  UNIQUE KEY `email` (`email`),
  UNIQUE KEY `email_2` (`email`),
  UNIQUE KEY `email_3` (`email`),
  UNIQUE KEY `userid` (`userid`),
  UNIQUE KEY `email_4` (`email`),
  KEY `id` (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=66 ;

--
-- Dumping data for table `user`
--

INSERT INTO `user` (`userid`, `name`, `email`, `pass`, `timestamp`, `id`) VALUES
('59e3950737b1f', 'ram', 'ram@gmail.com', 'rampwd', '2017-10-15 17:04:07', 59),
('59e3a5d94dfbd', 'gaurang', 'gnt3131@gmail.com', 'gaurangpwd', '2017-10-15 18:15:53', 64);


index.php

<html>
<head>
<title></title>

</head>

<body>
<center>
<h1> ADD USER</H1>
<form action="index.php" method="post">
name=<input type ="text" name="name"required/></br>
password=<input type ="text" name="pass" requierd /></br>
email=<input type ="text" name="email" required /></br></BR>
<input type ="submit" name="submit" VALUE ="INSERT"/></br>

</form>
</center>




<?php 
$connection=mysqli_connect('localhost','root','root','crud');


if(isset($_POST['submit'])){

    $name = $_POST['name'];
    $email = $_POST['email'];
    $pass = $_POST['pass'];
    $userid=uniqid();

if(mysqli_query($connection,"insert into user(userid,name,email,pass)values('$userid','$name','$email','$pass')"))
{
    echo"<H2>succesfully insert query</H2>";

}   
}
?>

<div align="center">
<table border="2" width="600">
<tr>
<th>USERID</th>
<th>NAME</th>
<th>EMAIL</th>
<th>PASSWORD</th>
<th>DATE CREATED </th>
<th>EDIT</th>
<th>DELETE</th>
</tr></div>
<?php
$connection=mysqli_connect('localhost','root','root','crud');

if(isset($_REQUEST['del'])){
    $del_id= $_REQUEST['del'];

if(mysqli_query($connection,"delete from user where id =$del_id"))
{
    echo"<h2>selected user of is deleted succesfully";
}





}
$run=mysqli_query($connection,"select * from user");



while($row=mysqli_fetch_array($run))
{

    $showuserid=$row[0];
    $showname=$row[1];
    $showemail=$row[2];
    $showpass=$row[3];
    $showdate=$row[4];
    $showid=$row[5];

    echo"<tr>
    <td>$showuserid</td>
    <td>$showname</td>
    <td>$showemail</td>
    <td>$showpass</td>
    <td>$showdate</td>
    <td><a href='edit.php?edit=$showid'>EDIT</td>
    <td><a href='?del=$showid'>DELETE</td>  
    </tr>
    ";
}




?>
</body>
</html>

-------------------------
edit.php

<?php
$connection=mysqli_connect('localhost','root','root','crud');
$edit=$_REQUEST['edit'];
$run=mysqli_query($connection,"select * from user where id = '$edit'");


while($row=mysqli_fetch_array($run))
{

    $name=$row[1];
    $email=$row[2];
    $pass=$row[3];
    $id=$row[5];
}
?>



<html>
<body>
<center>
<h1> EDIT USER</H1>
<form action="edit.php?edit_form =<?php echo $id ?>" method="post">
name=<input type ="text" name="uname" value="<?php echo $name ?>"/></br>
password=<input type ="text" name="upass" value="<?php echo $pass ?>"  /></br>
email=<input type ="text" name="uemail" value="<?php echo $email ?>" /></br> </BR>
<input type ="submit" name="uedit" VALUE ="Edit"/></br>

</form>
</center>
</body>
</html>

<?php
$connection=mysqli_connect('localhost','root','root','crud');

if(isset($_POST['uedit']))
{
    $uid= $_REQUEST['edit_form'];
    $uname= $_POST['uname'];
    $upass= $_POST['upass'];
    $uemail= $_POST['uemail'];

    if(mysqli_query($connection,"update user set name='$uname',email='$uemail',pass='$upass' where  id='$uid' "))
    {
                header("location:index.php");
    }
}


----

Answer 1

在你的edit.php文件中，将action =“edit.php？edit_form =”改为action =“”并添加输入类型=“隐藏”name =“id”value =“'。$ id。'”;进入你的形式如下......

.truckIcon{
    background-image: url(../images/icons/favicon.png);
    background-repeat: no-repeat !important;
    width:80px;
    height:80px;
    display: inline-block;
}

Answer 2

检查此行中的index.php：

<td><a href='edit.php?edit=$showid'>EDIT</td>

可能会发生两件事

第一： - $ showid为空，当您点击编辑按钮时，它会发送一个空值。

或第二： - 在edit.php中检查以下行：

$run=mysqli_query($connection,"select * from user where id = '$edit'");

像这样改变

$run=mysqli_query($connection,"select * from user where id = '".$_GET['edit']."'");

php中的CRUD操作...在edit.php中获取错误

2 个答案: