如何在此循环中选择其他所有结果? [PHP]

时间:2017-10-14 12:23:26

标签: php mysql

我有这个循环输出到图表。 随着时间的推移,我的“历史”表格中的数据会急剧增长,我希望通过选择其他结果来减少输出到图表上的数量。

如何使用我的代码执行此操作?

<?php

    $cdate = 0;   
    $counter = 0;

    $sql = "SELECT * FROM history WHERE time < '$ctime' ORDER BY time asc";
    $result = $conn->query($sql);

    if ($result->num_rows > 0) {
        while($row = $result->fetch_assoc()) {
            $cdate = ($row["time"]);

            $sql1 = "SELECT AVG(value) AS avgval FROM history WHERE time = '$cdate' AND time < '$ctime'";
            $result1 = $conn->query($sql1);

            if ($result1->num_rows > 0) {  
                while($row1 = $result1->fetch_assoc()) {   
                    $avgval = $row1["avgval"];
                    echo "[new Date((".($row["time"] * 1000).")), ".$avgval."],";    

                }  
            }
        }     
    }
?>

例如,如果我在我的表(历史记录)中有这个:

[id] --- [ticker] --- [value] --- [time]

1 --- Group1 --- 100 --- 730

2 ---第2组--- 200 --- 730

3 ---第1组--- 110 --- 740

4 ---第2组--- 235 --- 740

5 ---第1组--- 310 --- 750

6 ---第2组--- 485 --- 750

如何输出#1,#2的平均值和#5,#6的平均值 - 忽略#4和#5?

1 个答案:

答案 0 :(得分:1)

<?php
$cdate = 0;   
$counter = 0;

$sql = "SELECT * FROM history WHERE time < '$ctime' ORDER BY time asc";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) {
        $cdate = ($row["time"]);

        $sql1 = "SELECT AVG(value) AS avgval FROM history WHERE time = '$cdate' AND time < '$ctime'";
        $result1 = $conn->query($sql1);

        $i = 0; // incrementor
        if ($result1->num_rows > 0) {  
            while($row1 = $result1->fetch_assoc()) {   
                ++$i; // plus one
                if($i % 2 == 0) { // check if $i is even          
                    $avgval = $row1["avgval"];
                    echo "[new Date((".($row["time"] * 1000).")), ".$avgval."],";    
                }
            }  
        }
    }     
}
?>