Question

我有一个列表字典，并想知道是否有一种获得所有常用值的好方法。例如：

Dictionary<int, List<string>> myDictionary = new Dictionary<int, List<string>>();

并且在其中我说了4个键，每个键都有一个列表，我想获得字典中包含'Oscar'，'Pablo'，'John'的所有值。

注意：我不知道我在寻找什么，我只是得到这本字典，需要找到所有三个列表中的所有名称。

返回示例：

说我有一本带

的字典

Key=1 Value = List with {'Oscar', 'John','Pablo','Pedro'}
Key=2 Value = List with {'Duvan','Samuel','Pablo','Pedro'}
Key=3 Value = List with {'Camilo','Pablo','Julian'}

Return a list of List with {'Pablo'}

任何帮助都将不胜感激。

Answer 1

首先从列表中收集所有名称：

var allNames = dict.SelectMany(p => p.Value).Distinct().ToList();

现在您可以按如下方式过滤此列表：

var res = allNames
    .Where(s => dict.Count(p => p.Value.Contains(s)) == dict.Count)
    .ToList();

Answer 2

我会这样看：

var myDictionary = new Dictionary<int, List<string>>()
{
    { 1, new List<string>() { "Oscar", "Pablo", "John" } },
    { 2, new List<string>() { "Foo", "Hello", "World" } },
};

var names = new HashSet<string>() { "John", "Oscar", "Pablo"};

var matchesAll = myDictionary.Values.Where(v => names.All(n => v.Contains(n)));

var matchesAny = myDictionary.Values.Where(v => names.Any(n => v.Contains(n)));

最后两个选择取决于您是否希望所有单词匹配或任何单词。

根据您的评论，如果您想要所有字典值中常见的名称列表，那么您可以这样做：

var myDictionary = new Dictionary<int, List<string>>()
{
    { 1, new List<string>() { "Oscar", "Pablo", "John" } },
    { 2, new List<string>() { "Foo", "John", "World" } },
};

var commonInAll = myDictionary.Values.Aggregate((x, y) => x.Intersect(y).ToList());

在这种情况下，您只会在最终{ "John" }列表中获得commonInAll。

Answer 3

你可以试试这个：

 Dictionary<int, List<string>> myDictionary = new Dictionary<int, List<string>>();
        myDictionary.Add(1, new List<string>()
            {
                "Oscar", "Pablo", "John"
            });
        myDictionary.Add(2, new List<string>()
            {
                "Foo", "Hello", "World"
            });

        var result = myDictionary.Where(c => c.Value.Contains("Oscar") && c.Value.Contains("Pablo") && c.Value.Contains("John")).ToDictionary(c => c.Key, c => c.Value);

Answer 4

var namesToFilter = new List { ＆＃34;约翰＆＃34 ;, ＆＃34;奥斯卡＆＃34 ;, ＆＃34;巴勃罗＆＃34;};

Dictionary<int, List<string>> myDictionary = new Dictionary<int, List<string>>
{
    {1, new List<string> { "John", "Oscar", "Pablo"}},
    {2, new List<string> { "Oscar", "Olivia"}},
    {3, new List<string> { "Pablo", "Paula"}},
    {4, new List<string> { "Steve", "Stella"}},
};
var matchedKeys= myDictionary
.Where(d => namesToFilter.Where(str => d.Value.Any(v => v == str)).Count() == namesToFilter.Count())
.ToDictionary(kvp => kvp.Key, kvp => kvp.Value);

Console.Write(matchedKeys);

Answer 5

试试这个：

        myDictionary.Add(1, new List<string>() { "Oscar", "Pablo" });
        myDictionary.Add(2, new List<string>() { "John", "OtherName" });

        //Returns item from myDictionary that contains Oscar. Modify where linq query to your necessity
        Dictionary<int, List<string>> myNewDic = myDictionary.Where(dicItem => dicItem.Value.Contains("Oscar")).ToDictionary(dicItem => dicItem.Key, dicItem => dicItem.Value);

列表和检索常见值的字典

5 个答案: