Question

如果用户输入无效的重量或年龄，程序应立即显示错误消息并结束程序。输入年龄和体重后，我的程序会显示错误消息。谁能帮我？示例：用户为switch语句输入1以选择输入以月为单位的年龄和以kg为单位的体重。如果用户输入-5个月，它应立即显示错误消息并结束程序。相反，我的程序所做的是在为年龄输入-5之后它将提示用户然后输入权重。输入重量后，它会给我错误信息并结束我的程序。任何帮助都感激不尽。

 import java.util.Scanner;
 import java.lang.Math;
 public class infant{

public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int number;
double ageMonths = 0;
double ageYears = 0;
double weightPounds = 0;
double weightKg = 0;


System.out.println( "Choice 1 input the age in months, then weight in kilograms");          // this tells the user what the numbers 1-4 does when chosen
System.out.println( "Choice 2 input the age in years, weight in kilograms");
System.out.println( "Choice 3 input the age in months, weight in pounds");
System.out.println( "Choice 4 input the age in years, weight in pounds");


number =sc.nextInt();

if(number<=4 && number>=1){                                                  // if statement that makes the user enter a value from 1 to 4 for the switch statment.
        System.out.println("valid number selection");
    }else{ System.out.println("need to choose a number between 1 and 4");
        return;
    }

 switch(number){                                                                    // switch statment that allows the user to choose how they want to enter the height and weight 
    case 1: System.out.println("age in months: ");  ageMonths =sc.nextDouble();
            System.out.println("weight in kilograms: "); weightKg =sc.nextDouble();
            ageYears = ageMonths * 0.0833334;                                          // this switch statment also converts Kg to pounds and years to months in order for math equation in the if statement at then end of the program to work. 
            weightPounds = weightKg * 2.20462; 
            break;
    case 2: System.out.println("age in years: "); ageYears =sc.nextDouble();
            System.out.println("weight in kilograms: "); weightKg =sc.nextDouble();
            ageMonths = ageYears * 12; 
            weightPounds = weightKg * 2.20462; 
            break;
    case 3: System.out.println("age in months: "); ageMonths =sc.nextDouble();
            System.out.println("weight in pounds: "); weightPounds =sc.nextDouble();
            ageYears = ageMonths * 0.0833334;
            weightKg = weightPounds * 0.453592;
            break;
    case 4: System.out.println("age in years: "); ageYears =sc.nextDouble();
            System.out.println("weight in pounds: "); weightPounds =sc.nextDouble();
            ageMonths = ageYears * 12; 
            weightKg = weightPounds * 0.453592; 
            break;
    default: System.out.println("you entered in an invalid number"); 

}    

 if(ageMonths<=24 && ageMonths>-0.1){                                        // if statement that makes sure the ages are in the correct range
     System.out.println("valid age input");
    }else if(ageYears>-0.1 && ageYears<=2){
        System.out.println("valid age input");
    }else{ System.out.println("You entered a invaild age 0 to 24 months only");
        return;
}

    if(weightPounds>=4.40925 && weightPounds<=33.0693 || weightKg>=2 && weightKg<=15){      // if statement that makes sure the weight are in the correct range
        System.out.println("valid weight input");
    }else{ System.out.println("You entered a invaild weight 2kg to 15kg only");
        return;
    }




    if(weightKg >= ageYears * ageMonths / 3 + 2 && weightKg <= 5 * ageYears * ageMonths / 12 + 5){ // if statement that does a math equation to determine if your infant is healthy or not
        System.out.println(" your infant is healthy");
    }else{ System.out.println(" your infant is not healthy");
    }

     }
     }

Answer 1

检查重量和月份的代码，您在两个不同的功能中保存代码，然后在输入月份后在开关盒内部，然后调用输入该月份的功能，然后您可以执行相同的操作重量的东西，这样你就可以得到你想要的结构..请问你是否需要任何澄清。

function checkMonths(double ageMonths){
if(ageMonths<=24 && ageMonths>-0.1){                                        // if statement that makes sure the ages are in the correct range
 System.out.println("valid age input");
}else{ System.out.println("You entered a invaild age 0 to 24 months only");
    return;
}
}
function checkYears(double ageYears){
if(ageYears>-0.1 && ageYears<=2){
    System.out.println("valid age input");
}else{ System.out.println("You entered a invaild age 0 to 24 months only");
    return;
}
}


function checkWeights(double weightPounds){

if(weightPounds>=4.40925 && weightPounds<=33.0693 || weightKg>=2 && weightKg<=15){      // if statement that makes sure the weight are in the correct range
    System.out.println("valid weight input");
}else{ System.out.println("You entered a invaild weight 2kg to 15kg only");
    return;
}

 }

根据您的用法更改函数参数中的变量名称。

Answer 2

如果你真的想用无效输入结束你的程序，你总是可以使用System.exit（0）而不是“return”。这保证会结束该计划。

例如：

 if(number<=4 && number>=1){                                                  // if statement that makes the user enter a value from 1 to 4 for the switch statment.
    System.out.println("valid number selection");
}else{ System.out.println("need to choose a number between 1 and 4");
    System.exit(0);
}

除非我弄错了，否则应该在print语句之后立即终止主线程。

当有多个if语句时立即显示错误消息。输入两个程序后，我的程序显示错误消息

2 个答案: