在UILocalNotification弃用后检查是否启用了用户通知

时间:2017-10-10 10:13:18

标签: ios cocoa-touch usernotifications

在我的应用中,我希望能够检查用户是否启用了通知。在iOS 10中,我使用委托中的检查来完成此操作。

现在不推荐使用此检查,我想更新它,但我无法弄清楚在iOS 11中使用什么。

弃用警告如下:

  在iOS 10.0中不推荐使用

currentUserNotificationSettings:使用   UserNotifications Framework的 - [UNUserNotificationCenter   getNotificationSettingsWithCompletionHandler:]和    - [UNUserNotificationCenter getNotificationCategoriesWithCompletionHandler:]

我已尝试在此警告的帮助下更新代码,但我无法理解。

如果有人可以建议任何方式获得这样的支票,那将会有很大帮助。我在iOS 10中使用的代码如下所示,谢谢。

let notificationType = UIApplication.shared.currentUserNotificationSettings!.types
if notificationType == [] {
    print("Notifications are NOT enabled")
} else {
    print("Notifications are enabled")
}

3 个答案:

答案 0 :(得分:23)

第1步:import UserNotifications

第2步:

UNUserNotificationCenter.current().getNotificationSettings { (settings) in
  if settings.authorizationStatus == .authorized {
    // Notifications are allowed
  }
  else {
    // Either denied or notDetermined
  }
}

检查设置对象以获取更多信息。

答案 1 :(得分:7)

第一步: -  您必须将头文件添加为

import UserNotifications

我使用 checkpushNotification 方法检查用户是否启用了通知。使用从AppDelegate类的didFinishLaunchingWithOptions调用此方法。希望它会帮助你,如果有任何问题,请在下面评论。

最后一步: -

func checkPushNotification(){
        if #available(iOS 10.0, *) {
            UNUserNotificationCenter.current().getNotificationSettings(){ (setttings) in

                switch setttings.authorizationStatus{
                case .authorized:

                    print("enabled notification setting")

                case .denied:

                    print("setting has been disabled")

                case .notDetermined:
                    print("something vital went wrong here")
                }
            }
        } else {

            let isNotificationEnabled = UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert)
            if isNotificationEnabled{

                print("enabled notification setting")
            }else{

                print("setting has been disabled")
            }
        }
    }

如果你想要启用或禁用某些布尔输出,那么你应该实现完成处理程序来解决它。

func checkPushNotification(checkNotificationStatus isEnable : ((Bool)->())? = nil){

        if #available(iOS 10.0, *) {
            UNUserNotificationCenter.current().getNotificationSettings(){ (setttings) in

                switch setttings.authorizationStatus{
                case .authorized:

                    print("enabled notification setting")
                    isEnable?(true)
                case .denied:

                    print("setting has been disabled")
                    isEnable?(false)
                case .notDetermined:

                    print("something vital went wrong here")
                    isEnable?(false)
                }
            }
        } else {

            let isNotificationEnabled = UIApplication.shared.currentUserNotificationSettings?.types.contains(UIUserNotificationType.alert)
            if isNotificationEnabled == true{

                print("enabled notification setting")
                isEnable?(true)

            }else{

                print("setting has been disabled")
                isEnable?(false)
            }
        }
    }

并将此简单称为

  self.checkPushNotification {  (isEnable) in
    print(isEnable)
    // you know notification status.
}

答案 2 :(得分:0)

我认为您可以致电UIApplication.shared.isRegisteredForRemoteNotifications