Question

我遇到了关于json结果的联合操作的问题，因为我的嵌套json查询结果得到了他们的双引号转义，导致我的应用程序中的解析错误。这是一个例子：

SELECT DISTINCT s.*,
JSON_QUERY((select * from SomeTable WHERE Id = 'some ID' FOR JSON PATH, WITHOUT_ARRAY_WRAPPER)) AS ExampleColumn from [SomeOtherTable] sot where sot.Id = 'some other ID' 
UNION ALL
SELECT DISTINCT S1.*, JSON_QUERY((select * from SomeTable WHERE Id = 'some other other ID' FOR JSON PATH, WITHOUT_ARRAY_WRAPPER)) AS ExampleColumn from [SomeOtherTable] sot1 where sot1.Id = 'some other other other ID' FOR JSON PATH

结果是正确的，只有嵌套的JSON_QUERY结果转义了双引号。有人可以帮帮我吗？

Answer 1

您的查询将json转换为文本，这就是为什么第二个json将它们作为字符串线程并添加转义双引号。

你可以试试这个。我希望它可以帮助你。

SELECT STRING_AGG (JsonText,',') FROM (
    SELECT ( SELECT DISTINCT sot.*, ExampleColumn.*
             FROM 
                [SomeOtherTable] sot 
                OUTER APPLY(select * from SomeTable WHERE Id = 'some ID') AS ExampleColumn 
             WHERE 
                sot.Id = 'some other ID' FOR JSON AUTO, WITHOUT_ARRAY_WRAPPER ) JsonText

    UNION ALL

    SELECT ( SELECT DISTINCT sot1.*, ExampleColumn.*
             FROM 
                [SomeOtherTable] sot1 
                OUTER APPLY((select * from SomeTable WHERE Id = 'some other other ID')) AS ExampleColumn 
             WHERE sot1.Id = 'some other other other ID' FOR JSON AUTO, WITHOUT_ARRAY_WRAPPER ) JsonText
)

在json结果上的Transact SQL union all转义嵌套的json查询

1 个答案: