Question

使用Python与Selenium自动填充具有多个可折叠选项的页面中的时间表。

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下面的代码是星期一折叠，选择＆＃34;突破＆＃34;选项，然后星期二崩溃，什么都不做，再次回到星期一，做了所需要的但没有做任何反对＆＃34;突破＆＃34;这一次然后退出。实际上，我希望它在周一崩溃，选择选项，使用发送键填充时间;然后在周二崩溃，选择选项，使用发送键填充时间;然后退出打印＆＃34;所有日期都已填满＆＃34;。时间正在填充[16:59]和[17:59]而不是[16:00]和[17:00]。＆＃34;所有日子都填满了＃34;永远不会被打印出来。

for i in range(2):
    if i == 2:
        print("All days filled")
        break
    CollapseList[i].click()
    project = wait_for_xpath(driver, "//select[@id='gvTimesheetDay0_ctl02_ddlPANPA']/option[@value='1']").click()
    print("Project Selected")
    some_app_name = wait_for_xpath(driver,
                         "//select[@id='gvTimesheetDay0_ctl02_ddlProject']/option[@value='000043']").click()
    print("App selected")
    wrk = wait_for_xpath(driver,
                         "//select[@id='gvTimesheetDay0_ctl02_ddlPayCode']/option[@value='000000000000318']").click()
    print("Code selected")
    time_in = wait_for_visibility(driver, "gvTimesheetDay0_ctl02_txtSignIn").send_keys("08:00")
    timeout = wait_for_visibility(driver, "gvTimesheetDay0_ctl02_txtSignOut").send_keys("16:00")
    breakout = wait_for_xpath(driver, "//select[@id='ddlMealBreak0']/option[@value='2']").click()
    # press = wait_for_visibility(driver, "lnkSubmit0").click()
    # print("Good " + Day[n] + " has been filled")
    # justclick = wait_for_xpath(driver, "//html").click()
    print(i)

带有范围的Python FOR循环重复并跳过第一次运行中的部分代码，并在下次运行时重复该代码

0 个答案: