我正在尝试使用VLCJ库编写带有Java的http视频流应用程序,但我遇到问题"您的输入无法打开"。
操作系统:Windows10 x64
import com.sun.jna.Native;
import com.sun.jna.NativeLibrary;
import uk.co.caprica.vlcj.binding.LibVlc;
import uk.co.caprica.vlcj.player.MediaPlayerFactory;
import uk.co.caprica.vlcj.player.headless.HeadlessMediaPlayer;
import uk.co.caprica.vlcj.runtime.RuntimeUtil;
import uk.co.caprica.vlcj.runtime.x.LibXUtil;
import java.io.File;
/**
* An example of how to stream a media file over HTTP.
* <p>
* The client specifies an MRL of <code>http://127.0.0.1:5555</code>
*/
public class VideoStream extends VlcjTest{
public static void main(String[] args) throws Exception {
System.setProperty("VLC_PLUGIN_PATH", "D:\\Program Files\\VideoLAN\\VLC\\plugins");
File vlcInstallPath = new File("D:\\Program Files\\VideoLAN\\VLC");
NativeLibrary.addSearchPath(
RuntimeUtil.getLibVlcLibraryName(), vlcInstallPath.getAbsolutePath());
Native.loadLibrary(RuntimeUtil.getLibVlcLibraryName(), LibVlc.class);
LibXUtil.initialise();
String media = "D://demo.mp4";
String options = formatHttpStream("127.0.0.1", 5555);
System.out.println("Streaming '" + media + "' to '" + options + "'");
MediaPlayerFactory mediaPlayerFactory = new MediaPlayerFactory();
HeadlessMediaPlayer mediaPlayer = mediaPlayerFactory.newHeadlessMediaPlayer();
mediaPlayer.playMedia(media, options);
// Don't exit
Thread.currentThread().join();
}
private static String formatHttpStream(String serverAddress, int serverPort) {
StringBuilder sb = new StringBuilder(60);
sb.append(":sout=#duplicate{dst=std{access=http,mux=ts,");
sb.append("dst=");
sb.append(serverAddress);
sb.append(':');
sb.append(serverPort);
sb.append("}}");
return sb.toString();
}
}
和结果:
[000000001a948be0] access_output_http access out: Consider passing --http-host=IP on the command line instead.
[000000001aa2def0] core input error: open of `D://demo.mp4' failed
[000000001aa2def0] core input error: Your input can't be opened
[000000001aa2def0] core input error: VLC is unable to open the MRL 'D://demo.mp4'. Check the log for details.
答案 0 :(得分:0)
问题出在
String media = "D://demo.mp4";
根据评论的建议。在D:
之后 // ,它将被视为协议名称。
以下变体之一适合您:
String media = "D:/demo.mp4";
前提是playMedia
支持本地文件路径。或
String media = new File("D:/demo.mp4").toURI().toURL();
如果需要URL字符串。