Question

虽然LeanFT使用JUnit作为其测试运行器，但它似乎没有实现'TestRule'。这不包括其他地方描述的“标准”方法。

How to Re-run failed JUnit tests immediately?

任何人都有解决方案吗？

Answer 1

您似乎提到报告没有测试结果的事实。事实上，使用TestRule时，似乎不再自动报告。

但是，您可以手动报告您要报告的内容。

以下是Junit测试的示例，该测试报告我们希望报告的内容。

import com.hp.lft.report.CaptureLevel;
import com.hp.lft.report.ReportLevel;
import com.hp.lft.report.Reporter;
import com.hp.lft.sdk.web.Browser;
import com.hp.lft.sdk.web.BrowserFactory;
import com.hp.lft.sdk.web.BrowserType;
import org.junit.Rule;
import org.junit.Test;
import org.junit.rules.*;
import org.junit.runner.Description;
import org.junit.runners.model.Statement;
import unittesting.UnitTestClassBase;
import org.junit.After;
import org.junit.AfterClass;
import org.junit.Before;
import org.junit.BeforeClass;

public class RetryTest extends UnitTestClassBase {
    @BeforeClass
    public static void setUpBeforeClass() throws Exception {
        instance = new LeanFtTest();
        globalSetup(LeanFtTest.class);
    }

    @AfterClass
    public static void tearDownAfterClass() throws Exception {
        globalTearDown();
    }


    public class Retry implements TestRule {
        private int retryCount;

        public Retry(int retryCount) {
            this.retryCount = retryCount;
        }

        public Statement apply(Statement base, Description description) {
            return statement(base, description);
        }

        private Statement statement(final Statement base, final Description description) {
            return new Statement() {
                @Override
                public void evaluate() throws Throwable {
                    Throwable caughtThrowable = null;

                    // implement retry logic here
                    for (int i = 0; i < retryCount; i++) {
                        try {
                            base.evaluate();
                            return;
                        } catch (Throwable t) {
                            caughtThrowable = t;
                            System.err.println(description.getDisplayName() + ": run " + (i+1) + " failed");
                        }
                    }
                    System.err.println(description.getDisplayName() + ": giving up after " + retryCount + " failures");
                    throw caughtThrowable;
                }
            };
        }
    }

    @Rule
    public Retry retry = new Retry(3);

    @Test
    public void test2() throws  Exception{
        Reporter.startReportingContext("Reporting for test2");
        Reporter.reportEvent("Reporting", "Reporting stuff", Status.Passed);
        Reporter.reportEvent("Reporting", "Reporting some more stuff", Status.Failed);
        Reporter.endReportingContext();
        Object o = null;
        o.equals("foo");
    }
}

这就是它的样子：

如何使用Junit测试向reft添加重试逻辑？

1 个答案: