我是C ++的新手,我正在上课。该计划是两人之间的Tic Tac Toe游戏。我已经完成了一个不使用函数的程序版本,我试图利用它们。
我想编辑一个函数中的数组并输出稍后在程序中使用的函数。
这是代码;
// This is a assessment project which plays ticTacToe between two players.
#include <iostream>
using namespace std;
int main() {
void displayBoard(char ticTacToeGame[][3]); // sets up use of displayBoard()
char userPlay(); // sets up use of userPlay()
char addplayToBoard(char play, char ticTacToeGame[][3] ); // sets up use of addPlayToBoard()
char ticTacToeGame[3][3] = {'1', '2', '3', '4', '5', '6', '7', '8', '9'}; // game board array
// declaration of variables
char play;
displayBoard(ticTacToeGame); // displays the board to user
play = userPlay(); // gets users play and stores it as a char
return 0;
} // end of main()
// function used to display the board
void displayBoard(char ticTacToeGame[][3]) {
// display board
for (int row = 0; row < 3; row++) {
cout << endl;
for (int column = 0; column < 3; column++) {
cout << "| " << ticTacToeGame[row][column] << " ";
}
cout << "|\n";
if (row < 2) {
for (int i = 0; i < 19; i++) {
cout << "-";
}
}
}
} // end of displayBoard()
// function used to get users play
char userPlay() {
// declaration of variables
char play;
cout << "Play: ";
cin >> play;
cout << endl;
return play;
} // end of userPlay()
// function used to add users play to board
char addPlayToBoard(char play, char ticTacToeGame[][3]) {
for (int row = 0; row < 3; row++) {
for (int column = 0; column < 3; column++) {
if (ticTacToeGame[row][column] == play){
ticTacToeGame[row][column] = 'O';
}
}
}
return ticTacToeGame;
} // end of addPlayToBoard()
我该怎么做?
答案 0 :(得分:2)
一个好的C ++课程将涵盖数组之前的类。你在这里使用的那种阵列是一个原始的构建块,这就是你在苦苦挣扎的原因。
我们在这里猜测你的课程已经涵盖了一些内容,但这就是你通常的做法:
class Board {
char fields[3][3];
public:
// Class methods
};
以下是重要原因:C ++类是完整的类型,可以从函数返回,就像int
值一样。但通常甚至不需要:类方法在该类上就地工作。