Question

所以我已经完成了基础设置。

这是我的用户模型：

# == Schema Information
# Schema version: 20110102225945
#
# Table name: users
#
#  id                   :integer         primary key
#  email                :string(255)
#  encrypted_password   :string(128)
#  password_salt        :string(255)
#  reset_password_token :string(255)
#  remember_token       :string(255)
#  remember_created_at  :datetime
#  sign_in_count        :integer
#  current_sign_in_at   :datetime
#  last_sign_in_at      :datetime
#  current_sign_in_ip   :string(255)
#  last_sign_in_ip      :string(255)
#  created_at           :datetime
#  updated_at           :datetime
#  username             :string(255)
#  f_name               :string(255)
#  l_name               :string(255)
#

class User < ActiveRecord::Base
  # Include default devise modules. Others available are:
  # :token_authenticatable, :confirmable, and :lockable
  devise :database_authenticatable, :registerable, :timeoutable,
         :recoverable, :rememberable, :trackable, :validatable

  # Setup accessible (or protected) attributes for your model
  attr_accessible :email, :password, :password_confirmation, :remember_me

  has_and_belongs_to_many :projects
  has_many :stages
  has_many :uploads
  has_many :comments
  has_many :assignments
  has_many :roles, :through => :assignments
  has_and_belongs_to_many :owners,
                  :class_name => "User",
                  :association_foreign_key => "owner_id",
                  :join_table => "ownership"

  def role_symbols
    roles.map do |role|
      role.name.underscore.to_sym
    end
  end  
end

我的角色模型如下所示：

# == Schema Information
# Schema version: 20101117094659
#
# Table name: roles
#
#  id         :integer         not null, primary key
#  name       :string(255)
#  created_at :datetime
#  updated_at :datetime
#

class Role < ActiveRecord::Base
    has_many :assignments
    has_many :users, :through => :assignments
end

作业看起来像这样：

# == Schema Information
# Schema version: 20101117094659
#
# Table name: assignments
#
#  id         :integer         not null, primary key
#  created_at :datetime
#  updated_at :datetime
#  user_id    :integer
#  role_id    :integer
#

class Assignment < ActiveRecord::Base
    belongs_to :role
    belongs_to :user
end

我的所有权表格包含owner_id和user_id。

我的表中有一个对应两个不同用户的条目。所以我的问题是，我如何与该join_table的用户/记录进行交互。

我想知道以下内容：

在我的rails控制台中，如何与该所有权表中的数据进行交互？我尝试了owner.all，Owner.all，ownership.all，owners.all，但都无济于事。因此，考虑到这种结构与常规关联有点不同，我该怎么做？
在我的ERB中，如何列出与current_user关联的所有“用户”？我访问与当前用户关联的项目的方式如下：current_user.projects.each do |project|然后我可以project.name等。但不太确定如何做到这一点。

由于

Answer 1

这对我有用（示例是父/子关系，但概念上与所有者/拥有者相同）

# The corresponding table has a parent_id and a child_id columns
class Relation < ActiveRecord::Base
  belongs_to :parent, :class_name => “User”
  belongs_to :child, :class_name => “User”
end

class User < ActiveRecord::Base
  # The user’s parents
  # Get them from the relations where
  # the current user is a child
  has_many :parent_relations,
           :class_name => ‘Relation’,
           :foreign_key => ‘child_id’

  has_many :parents,
           :through => :parent_relations

  # The user’s children
  # Get them from the relations where
  # the current user is a parent
  has_many :children_relations,
           :class_name => ‘Relation’,
           :foreign_key => ‘parent_id’

  has_many :children,
           :through => :children_relations
end

在这种情况下，您可以在视图中使用以下内容

- current_user.parents.each do |parent|
  %p= parent.email # Since the parent is a User

希望这有帮助

如何让一个用户在Rails 3中“拥有”另一个用户？

1 个答案: