我在 MainActivity.java 中有一个onClick
切换方法,按钮以 Navigation.java 编程创建。初始菜单nav.mainMenu()
被正确调用,按钮按预期创建。我的问题是,当我点击按钮时,没有任何反应。
我在logcat中没有得到错误堆栈跟踪。我已经尝试将日志放入onclick方法,但它没有那么远。模拟器似乎工作,不会冻结或崩溃。
我假设当我将代码发送到菜单时,活动是在该类中?所以当我尝试使用onClickListener
中的MainActivity
时,它不知道它?
我也不确定 MainActivity.java v.getId()
中R.id.btnGame
应该期待什么?
MainActivity.java
public class MainActivity extends Activity implements View.OnClickListener {
public Navigation nav = new Navigation(this);
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.empty);
nav.mainMenu();
}
@Override
public void onClick(View v) {
switch(v.getId()) {
case R.id.btnGame:
nav.game();
break;
}
}
}
Navigation.java
public class Navigation {
Button btnGame;
Context mContext;
Navigation(Context mContext) {
this.mContext = mContext;
}
public void mainMenu() {
LinearLayout ll = new LinearLayout(mContext);
ll.removeAllViews();
LinearLayout.LayoutParams llP = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.MATCH_PARENT);
ll.setLayoutParams(llP);
ll.setOrientation(LinearLayout.VERTICAL);
LinearLayout.LayoutParams btnParams = new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT);
btnGame = new Button(mContext.getApplicationContext());
btnGame.setLayoutParams(btnParams);
btnGame.setText("Play Game");
ll.addView(btnGame);
Activity activity = (Activity) mContext;
activity.setContentView(ll);
}
public void game() {
Toast.makeText(mContext, "I dont see this", Toast.LENGTH_SHORT).show();
}
}
我尝试将.setOnClickListener()
添加到 Navigation.java 中的按钮,但我无法获得正确的上下文,我不知道这是否是缺少的。
将 Navigation.java 扩展到MainActivity或Activity会给我一个错误循环。
将应用程序构建到模拟器上后的Logcat:
09-30 17:43:59.655 7038-7038/? I/art: Not late-enabling -Xcheck:jni (already on)
09-30 17:43:59.655 7038-7038/? W/art: Unexpected CPU variant for X86 using defaults: x86
09-30 17:43:59.854 7038-7038/com.fomtirth.barcodebattle W/System: ClassLoader referenced unknown path: /data/app/com.fomtirth.barcodebattle-2/lib/x86
09-30 17:43:59.867 7038-7038/com.fomtirth.barcodebattle I/InstantRun: starting instant run server: is main process
09-30 17:44:00.230 7038-7066/com.fomtirth.barcodebattle I/OpenGLRenderer: Initialized EGL, version 1.4
09-30 17:44:00.230 7038-7066/com.fomtirth.barcodebattle D/OpenGLRenderer: Swap behavior 1
09-30 17:44:00.230 7038-7066/com.fomtirth.barcodebattle W/OpenGLRenderer: Failed to choose config with EGL_SWAP_BEHAVIOR_PRESERVED, retrying without...
09-30 17:44:00.230 7038-7066/com.fomtirth.barcodebattle D/OpenGLRenderer: Swap behavior 0
09-30 17:44:00.234 7038-7066/com.fomtirth.barcodebattle D/EGL_emulation: eglCreateContext: 0x9baa38c0: maj 2 min 0 rcv 2
09-30 17:44:00.241 7038-7066/com.fomtirth.barcodebattle D/EGL_emulation: eglMakeCurrent: 0x9baa38c0: ver 2 0 (tinfo 0x99a887d0)
09-30 17:44:00.293 7038-7066/com.fomtirth.barcodebattle D/EGL_emulation: eglMakeCurrent: 0x9baa38c0: ver 2 0 (tinfo 0x99a887d0)
09-30 17:44:00.400 7038-7066/com.fomtirth.barcodebattle D/EGL_emulation: eglMakeCurrent: 0x9baa38c0: ver 2 0 (tinfo 0x99a887d0)
09-30 17:44:00.460 7038-7066/com.fomtirth.barcodebattle D/EGL_emulation: eglMakeCurrent: 0x9baa38c0: ver 2 0 (tinfo 0x99a887d0)
答案 0 :(得分:2)
您无法从字段中分配上下文。您可能“无法分配权利”,因为您实际上获得了nullpointerexception并编辑了错误的位置。话虽如此,但不需要getApplicationContext()
。
另外,我是否可以建议您返回内容布局而不是将上下文转换为活动?
public Navigation nav;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
nav = new Navigation(this);
setContentView(nav.mainMenu());
}
@Override
public void onClick(View v) {
switch(v.getId()) {
case R.id.btnGame:
nav.game();
break;
}
}
乍一看,我发现你从未在按钮上设置点击监听器,所以你应该这样做。
例如
Context mContext;
View.OnClickListener mClickListener;
Navigation(Context context) {
this.mContext = context;
if (context instanceof View.OnClickListener) {
this.mClickListener = (View.OnClickListener) context ;
}
}
现在使用此
if (mClickListener!=null) {
button.setOnClickListener(mClickListener);
}
我也不确定我应该从MainActivity.java R.id.btnGame中的v.getId()中得到什么?
ID与变量名称不匹配。如果没有明确地给按钮添加ID,它将是-1