如何获得＆lt;和＆gt; x访问？

Question

如果此查询带我一些用户无法访问：

SELECT DISTINCT COUNT(table1.IdUtente) AS UserWithoutAccess
FROM  table1 
LEFT OUTER JOIN table2 ON table1.IdUtente = table2.IdAttivazione
WHERE (table1.Demo = 1) AND (table1.idRivenditore = 0) 
AND (table1.IdGruppo NOT IN (29, 130,117))
AND (table2.IdAttivazione IS NULL)

表格是：

如何为访问次数为+或超过x次的用户执行相同的查询。例如，用户访问超过600次，我该如何进行查询？ 感谢帮助 T.M。

Answer 1

SELECT idUtente, count(*) as LoginCount
FROM table1 A
JOIN table2 B ON A.idUtente = B.IdAttivazione
WHERE (table1.Demo = 1) AND (table1.idRivenditore = 0) 
AND (table1.IdGruppo NOT IN (29, 130,117))
GROUP BY idUtente
HAVING Count(*) > 600

• Inner Join确保您与至少登录过一次的用户合作
• 您需要从WHERE条件中删除table2.IdAttivazione IS NULL，因为只有在您查找没有登录的用户时才有效
• 有COUNT（*）＆gt; X将为您提供具有超过X个登录次数的登录（IdUtente）