我有一个简单的帖子来获取我的json对象。
在我的json中,我有两个或更多的广告系列,广告系列是一个数组。
在广告系列数组中我有插槽,插槽是一个内部有1个或更多base_image的数组。
我在每个广告系列的屏幕上显示。
max_slots
c_name
slots.base_image
这样我就可以展示每个广告系列名称,允许的最大广告位数以及每个广告系列中关联的图片。
AIM
我正在尝试为每个广告系列设置上传图片和预览图片,因此您只能看到上传到该广告系列的图片预览。
问题
目前我上传了一张图片,它会在所有广告系列的预览中显示,而不是单个广告系列。
见下图:
HTML
<body ng-app="myApp">
<div ng-controller="Dashboard">
<!--FIRST ng-repeat-->
<div ng-repeat="campaign in campaigns" class="campaign-container">
<div class="container">
<h1>{{campaign.c_name}} {{$index}}</h1>
<strong>This Campaign you are allowed {{campaign.max_slots}} Images</strong>
<table class="table">
<thead>
<tr>
<th>Select File</th>
<th>Preview Image</th>
<th>Add to list</th>
<th>Images</th>
<!--<th>Remove Image</th>-->
<th>Save Campaign</th>
</tr>
</thead>
<tbody>
<tr>
<td> <!--UPLOAD IMAGE-->
<div class="upload-new">
<input id="fileinput" ng-model="file" type="file" ng-model-instant="" name="file"
accept="image/*"
onchange="angular.element(this).scope().uploadImage(this)">
</div>
<!--END-->
</td>
<td> <!--PREVIEW IMAGE-->
<div class="preview">
<img style="height: 100px; width: 100px" ng-src="{{preview}}" alt="preview image">
</div>
<!--END--></td>
<td>
<button ng-click="addImage()">Add image</button>
</td>
<td>
<div ng-repeat="slot in campaign.slots" class="slot">
<img ng-click="addImage()" style="height: 100px; width: 100px" ng-src="{{base_image}}"
alt="slot image">
<button ng-click="removeImage(slot)">Remove Image</button>
</div>
</td>
<!--<td>Remove button to be here</td>-->
<td>
<button ng-click="SaveImage()">Save to API</button>
</td>
</tr>
</tbody>
</table>
</div>
</div>
<!--END FIRST ng-repeat-->
</div>
</body>
的JavaScript
.controller('Dashboard', function ($scope, $http, $timeout) {
$scope.campaigns = [];
$scope.preview = '';
// $scope.slots = [];
$scope.maxSlots = [5];// this dynamic
$scope.uploadImage = function () {
// console.log('we are here');
input = document.getElementById('fileinput');
file = input.files[0];
size = file.size;
if (size < 650000) {
var fr = new FileReader;
fr.onload = function (e) {
var img = new Image;
img.onload = function () {
var width = img.width;
var height = img.height;
if (width == 1920 && height == 1080) {
$scope.preview = e.target.result;
$scope.perfect = "you added a image";
$scope.$apply();
} else {
$scope.notPerfect = "incorrect definitions";
}
};
img.src = fr.result;
};
fr.readAsDataURL(file);
} else {
$scope.notPerfect = "to big";
}
};
$scope.addImage = function (index) {
if ($scope.campaigns[index].slots.length < $scope.campaigns.maxSlots) {
$scope.campaigns[index].slots.push({
"slot_id": $scope.campaigns[index].slots.length + 1,
"base_image": $scope.preview,
"path_image": ""
});
} else {
window.alert("you have to delete a slot to generate a new one");
}
};
$scope.GetData = function () {
$http({
url: "http://www.site.co.uk/ccuploader/campaigns/getCampaign",
method: "POST",
date: {},
headers: {'Content-Type': 'application/json'}
}).then(function (response) {
// success
console.log('you have received the data ');
// console.log(response);
$scope.campaigns = response.data;
console.log("logging campaings", $scope.campaigns);
//$scope.slots = response.data[0].slots;
//$scope.maxSlots = response.data[0].maxSlots;
}, function (response) {
// failed
console.log('failed getting campaigns goo back to log in page.');
// console.log(response);
});
};
$scope.GetData();
})
答案 0 :(得分:2)
您的控制器中只有一个preview
变量,但每campaign
需要一个变量。您可能希望将广告系列的索引传递到uploadImage
函数中。
我不确定你做文件输入的方式是否正确(我自己做得不多),但你需要这样的东西:
模板:
<input type="file" onchange="angular.element(this).scope().uploadImage(this, $index)">
<img ng-src="{{campaign.preview}}" alt="preview image">
控制器:
$scope.uploadImage = function (element, index) {
// Remove this - there are many file inputs with this ID. Use the element or index arguments?
// input = document.getElementById('fileinput');
// ...
if (width == 1920 && height == 1080) {
$scope.campaigns[index].preview = e.target.result;
}
}
正如我在上面的评论中所提到的,您也在调用input = document.getElementById('fileinput');
来获取文件输入,但ng-repeat
将使用该ID创建许多输入。也许你应该使用传递给uploadImage(this, $index)
的输入或索引。如果由于某种原因您仍然需要使用getElementById
而不是使用您传入的元素,则可以使用索引生成唯一ID:
<input id="fileinput-{{ $index }}"
编辑:OP使用上面的答案进行了一些修改:
<强> HTML 强>
<input id="fileinput-{{ $index }}" ng-model="file" type="file" ng-model-instant="" name="file" accept="image/*" onchange="angular.element(this).scope().uploadImage(this)">
<强>控制器强>
$scope.uploadImage = function (element, index) {
console.log(element);
console.log(element.id);
str = element.id;
str = str.substr(str.indexOf('-') + 1);
console.log(str);
index = str;
// console.log('we are here');
input = element;
file = input.files[0];
size = file.size;
if (size < 650000) {
var fr = new FileReader;
fr.onload = function (e) {
var img = new Image;
img.onload = function () {
var width = img.width;
var height = img.height;
if (width == 1920 && height == 1080) {
console.log('we are here');
$scope.campaigns[index].preview = e.target.result;
// $scope.preview = e.target.result;
$scope.perfect = "you added a image";
$scope.$apply();
} else {
$scope.notPerfect = "incorrect definitions";
}
};
img.src = fr.result;
};
fr.readAsDataURL(file);
} else {
$scope.notPerfect = "to big";
}
};