Question

我正在使用带有pandas的jupyter笔记本，但是当我使用Spark时，我想使用Spark DataFrame来转换或计算而不是Pandas。请帮我将一些计算转换为Spark DataFrame或RDD。

数据帧：

df =
+--------+-------+---------+--------+
| userId | item  |  price  |  value |
+--------+-------+---------+--------+
|  169   | I0111 |  5300   |   1    |
|  169   | I0973 |  70     |   1    |
|  336   | C0174 |  455    |   1    |
|  336   | I0025 |  126    |   1    |
|  336   | I0973 |   4     |   1    |
| 770963 | B0166 |   2     |   1    |
| 1294537| I0110 |  90     |   1    |
+--------+-------+---------+--------+

1。使用熊猫计算：

(1)  userItem = df.groupby(['userId'])['item'].nunique()

，结果是一个Series对象：

+--------+------+
| userId |      |
+--------+------+
|  169   |   2  |
|  336   |   3  |
| 770963 |   1  |
| 1294537|   1  |
+--------+------+

2。使用乘法

data_sum = df.groupby(['userId', 'item'])['value'].sum()  --> result is Series object

average_played = np.mean(userItem)  --> result is number

(2)  weighted_games_played = data_sum * (average_played / userItem)

请帮我在Spark上使用Spark DataFrame和Opertors来做这个（1）和（2）

Answer 1

您可以使用以下内容实现（1）：

import pyspark.sql.functions as f
userItem=df.groupby('userId').agg(f.expr('count(distinct item)').alias('n_item'))

和（2）：

data_sum=df.groupby(['userId','item']).agg(f.sum('value').alias('sum_value'))

average_played=userItem.agg(f.mean('n_item').alias('avg_played'))

data_sum=data_sum.join(userItem, on='userId').crossJoin(average_played)

data_sum=data_sum.withColumn("weighted_games_played", f.expr("sum_value*avg_played/n_item"))

Answer 2

您可以定义如下方法：

import org.apache.spark.mllib.linalg.distributed.{RowMatrix}
import org.apache.spark.mllib.linalg.{Vectors,Matrices,DenseVector}
import org.apache.spark.sql.types.{StructType,StructField,DoubleType}
import org.apache.spark.{SparkConf,SparkContext}
object retain {
  implicit class DataFrameTransforms(left: DataFrame) {
  val dftordd = left.rdd.map{case row => 
  Vectors.dense(row.toSeq.toArray.map{x=>x.asInstanceOf[Double]})}
  val leftRM = new RowMatrix(dftordd)
    def multiply(right:DataFrame):DataFrame = {
      val matrixC = right.columns.map(col(_))
      val arr = right.select(array(matrixC:_*).as("arr")).as[Array[Double]].collect.flatten
      val rows = right.count().toInt
      val cols = matrixC.length
      val rightRM = Matrices.dense(cols,rows,arr).transpose
      val product = leftRM.multiply(rightRM).rows
      val x = product.map(r=>r.toArray).collect.map(p=>Row(p: _*))
      var schema = new StructType()
      var i = 0
      val t = cols
       while (i < t) {
        schema = schema.add(StructField(s"component${i}", DoubleType, true))
       i = i + 1
       }
      val err = spark.createDataFrame(sc.parallelize(x),schema)
err
}
}
}

并且仅在使用

之前

import retain._

假设您有两个名为df1（m×n）和df2（n×m）的数据帧

df1.multiply(df2)

Spark DataFrame运算符（nunique，multiplication）

2 个答案: