Datagrid不在Winforms中显示数据

时间:2017-09-22 07:46:28

标签: c# winforms datagridview datagrid

我是Winforms的新手,只是尝试了一个包含2个表单的示例应用程序。

  • Form1有文本框,组合框,单选按钮和提交按钮
  • Form2有一个datagrid,它应该显示Form1发送的数据。

Form1中

 DataFetch fetch ;
        
        public Form1()
        {
            InitializeComponent();

            fetch = new DataFetch();
            comboBox1.DataSource = fetch.getDesignation();
            comboBox1.DisplayMember = "Name";
            comboBox1.ValueMember = "Id";

            radioButton1.Checked = true;
        }
        
        private void button1_Click(object sender, EventArgs e)
        {
            Employee employee = new Employee();
            employee.Designation = comboBox1.SelectedText==""?"Admin":comboBox1.SelectedText;
            employee.IsCertified = radioButton1.Checked == true ? true : false;
            employee.name = textBox1.Text;
            Form2 form = new Form2(employee);
            form.Show();
        }

窗体2

 public partial class Form2 : Form
    {
        public Form2(Employee employee)
        { 
            InitializeComponent();
            dataGridView1.DataSource = employee;
        }
     }

Form2 Designer代码

 partial class Form2
    {
        /// <summary>
        /// Required designer variable.
        /// </summary>
        private System.ComponentModel.IContainer components = null;

        /// <summary>
        /// Clean up any resources being used.
        /// </summary>
        /// <param name="disposing">true if managed resources should be disposed; otherwise, false.</param>
        protected override void Dispose(bool disposing)
        {
            if (disposing && (components != null))
            {
                components.Dispose();
            }
            base.Dispose(disposing);
        }

        #region Windows Form Designer generated code

        /// <summary>
        /// Required method for Designer support - do not modify
        /// the contents of this method with the code editor.
        /// </summary>
        private void InitializeComponent()
        {
            this.dataGridView1 = new System.Windows.Forms.DataGridView();
            ((System.ComponentModel.ISupportInitialize)(this.dataGridView1)).BeginInit();
            this.SuspendLayout();
            // 
            // dataGridView1
            // 
            this.dataGridView1.ColumnHeadersHeightSizeMode = System.Windows.Forms.DataGridViewColumnHeadersHeightSizeMode.AutoSize;
            this.dataGridView1.Location = new System.Drawing.Point(72, 93);
            this.dataGridView1.Name = "dataGridView1";
            this.dataGridView1.Size = new System.Drawing.Size(240, 150);
            this.dataGridView1.TabIndex = 0;
            this.dataGridView1.CellContentClick += new System.Windows.Forms.DataGridViewCellEventHandler(this.dataGridView1_CellContentClick_1);
            // 
            // Form2
            // 
            this.AutoScaleDimensions = new System.Drawing.SizeF(6F, 13F);
            this.AutoScaleMode = System.Windows.Forms.AutoScaleMode.Font;
            this.ClientSize = new System.Drawing.Size(460, 346);
            this.Controls.Add(this.dataGridView1);
            this.Name = "Form2";
            this.Text = "Form2";
            ((System.ComponentModel.ISupportInitialize)(this.dataGridView1)).EndInit();
            this.ResumeLayout(false);

        }

        #endregion

        private System.Windows.Forms.DataGridView dataGridView1;
    }


虽然我能够在Form2的构造函数中获取数据,但我无法将其绑定到网格,在这种情况下显示到网格。

2 个答案:

答案 0 :(得分:1)

DataGridView's DataSource通常是一个集合,我不确定您为什么要尝试将单个对象绑定到它。但无论如何,您可以初始化单项List,然后将其绑定到datagridview1的数据源。

例如:

datagridview1.DataSource = new List<Employee> { employee };

答案 1 :(得分:0)

你可以轻松地做到这一点

您想要添加数据表并在表单2上发送的所有项目 然后在gridview

上绑定它

ittink它会帮助你