Question

您好我想在列表视图中添加更多图片，因为下面的代码只会在每一行中连续显示图像1和2。我想要做的是为每个不同的行显示不同的图像。这是下面的mycode;

感谢您的帮助。我不擅长java，请在必要时更改代码，然后我可以参考它。

公共类启动器扩展了ListActivity { 私有静态类EfficientAdapter扩展BaseAdapter { private LayoutInflater mInflater; 私有位图mIcon1; 私有位图mIcon2; 私有位图mIcon3; 私有位图mIcon4; 私有位图mIcon5; 私有位图mIcon6; 私有位图mIcon7; 私有位图mIcon8; 私有位图mIcon9; 私有位图mIcon10;

    public EfficientAdapter(Context context) {
        // Cache the LayoutInflate to avoid asking for a new one each time.
        mInflater = LayoutInflater.from(context);

        // Icons bound to the rows.
        mIcon1 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters1);
        mIcon2 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters2);
        mIcon3 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters3);
        mIcon4 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters4);
        mIcon5 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters5);
        mIcon6 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters6);
        mIcon7 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters7);
        mIcon8 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters8);
        mIcon9 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters9);
        mIcon10 = BitmapFactory.decodeResource(context.getResources(), R.drawable.starters10);
    }

    public int getCount() {
        return DATA.length;
    }

    public Object getItem(int position) {
        return position;
    }

    public long getItemId(int position) {
        return position;
    }

    public View getView(int position, View convertView, ViewGroup parent) {
        // A ViewHolder keeps references to children views to avoid unneccessary calls
        // to findViewById() on each row.
        ViewHolder holder;

        // When convertView is not null, we can reuse it directly, there is no need
        // to reinflate it. We only inflate a new View when the convertView supplied
        // by ListView is null.
        if (convertView == null) {
            convertView = mInflater.inflate(R.layout.starters, null);

            // Creates a ViewHolder and store references to the two children views
            // we want to bind data to.
            holder = new ViewHolder();

            holder.text = (TextView) convertView.findViewById(R.id.text01);
            holder.text = (TextView) convertView.findViewById(R.id.secondLine);
            holder.icon = (ImageView) convertView.findViewById(R.id.icon01);

            convertView.setTag(holder);
        } else {
            // Get the ViewHolder back to get fast access to the TextView
            // and the ImageView.
            holder = (ViewHolder) convertView.getTag();
        }

        // Bind the data efficiently with the holder.
        holder.text.setText(DATA[position]);
       holder.icon.setImageBitmap((position & 1) ==1 ? mIcon1 : mIcon2);


         return convertView;
    }

    static class ViewHolder {
        TextView text;
        ImageView icon;
    }
}

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setListAdapter(new EfficientAdapter(this));
}

private static final String[] DATA = {
    "Original nachos", "Toasted chicken and cheese quesadillas", "Chicken, lime and coriander nachos",
    "Spicy bean and cheese quesadillas", "Tuna and corn quesadillas", "Cheesy bean and sweetcorn nachos", "Crispy chicken, avocado and lime salad", "Beef and baby corn tostada",
    "Spicy mexican rice with chicken and prawns", "Chilli potato boats"};

}

Answer 1

我想要做的是为每个不同的行显示不同的图像

然后在每行中放入不同的图像。您可以通过getView()控制每行中的内容。您当前的实现在两个不同的图像之间进行迭代 - 将该逻辑更改为适合您应用的任何图像。

Here is a free excerpt从我的一本书中了解到这一点。

在listview中添加图像

1 个答案: