Question

我有一个带有文本框控件的Windows窗体应用程序，我只想接受整数值。在过去，我通过重载KeyPress事件并删除不符合规范的字符来完成这种验证。我查看了MaskedTextBox控件，但我想要一个更通用的解决方案，可以使用正则表达式，或者依赖于其他控件的值。

理想情况下，按下非数字字符会产生无结果或立即向用户提供有关无效字符的反馈。

Answer 1

两个选项：

请改用NumericUpDown。 NumericUpDown为您做过滤，这很好。当然，它还可以让用户点击键盘上的向上和向下箭头来增加和减少当前值。

处理相应的键盘事件以防止数字输入以外的任何事件。我在标准TextBox上使用这两个事件处理程序取得了成功：

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (!char.IsControl(e.KeyChar) && !char.IsDigit(e.KeyChar) &&
        (e.KeyChar != '.'))
    {
            e.Handled = true;
    }

    // only allow one decimal point
    if ((e.KeyChar == '.') && ((sender as TextBox).Text.IndexOf('.') > -1))
    {
        e.Handled = true;
    }
}

如果TextBox不允许小数位，则可以删除对'.'的检查（以及后续检查多个'.'）。如果您的TextBox应允许负值，您还可以添加'-'的支票。

如果您想限制用户使用的位数，请使用：textBox1.MaxLength = 2; // this will allow the user to enter only 2 digits

Answer 2

只是因为在一行中做事总是更有趣......

 private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
    {
        e.Handled = !char.IsDigit(e.KeyChar) && !char.IsControl(e.KeyChar);
    }

注意：这不会阻止用户复制/粘贴到此文本框中。这不是一种清理数据的安全方法。

Answer 3

我假设您从上下文和您使用的标签开始编写.NET C＃应用程序。在这种情况下，您可以订阅文本更改事件，并验证每个键击。

    private void textBox1_TextChanged(object sender, EventArgs e)
    {
        if (System.Text.RegularExpressions.Regex.IsMatch(textBox1.Text, "[^0-9]"))
        {
            MessageBox.Show("Please enter only numbers.");
            textBox1.Text = textBox1.Text.Remove(textBox1.Text.Length - 1);
        }
    }

Answer 4

这是一个简单的独立Winforms自定义控件，源自标准TextBox，只允许System.Int32输入（它可以很容易地适用于其他类型，如System.Int64等）。它支持复制/粘贴操作和负数：

public class Int32TextBox : TextBox
{
    protected override void OnKeyPress(KeyPressEventArgs e)
    {
        base.OnKeyPress(e);

        NumberFormatInfo fi = CultureInfo.CurrentCulture.NumberFormat;

        string c = e.KeyChar.ToString();
        if (char.IsDigit(c, 0))
            return;

        if ((SelectionStart == 0) && (c.Equals(fi.NegativeSign)))
            return;

        // copy/paste
        if ((((int)e.KeyChar == 22) || ((int)e.KeyChar == 3))
            && ((ModifierKeys & Keys.Control) == Keys.Control))
            return;

        if (e.KeyChar == '\b')
            return;

        e.Handled = true;
    }

    protected override void WndProc(ref System.Windows.Forms.Message m)
    {
        const int WM_PASTE = 0x0302;
        if (m.Msg == WM_PASTE)
        {
            string text = Clipboard.GetText();
            if (string.IsNullOrEmpty(text))
                return;

            if ((text.IndexOf('+') >= 0) && (SelectionStart != 0))
                return;

            int i;
            if (!int.TryParse(text, out i)) // change this for other integer types
                return;

            if ((i < 0) && (SelectionStart != 0))
                return;
        }
        base.WndProc(ref m);
    }

2017年更新：我的第一个回答有一些问题：

您可以键入比给定类型的整数更长的内容（例如2147483648大于Int32.MaxValue）;
更一般地说，对所输入的内容的结果没有真正的验证;
它只处理int32，你必须为每种类型（Int64等）编写特定的TextBox派生控件。

所以我提出了另一个更通用的版本，它仍然支持复制/粘贴，+和 - 符号等。

public class ValidatingTextBox : TextBox
{
    private string _validText;
    private int _selectionStart;
    private int _selectionEnd;
    private bool _dontProcessMessages;

    public event EventHandler<TextValidatingEventArgs> TextValidating;

    protected virtual void OnTextValidating(object sender, TextValidatingEventArgs e) => TextValidating?.Invoke(sender, e);

    protected override void WndProc(ref Message m)
    {
        base.WndProc(ref m);
        if (_dontProcessMessages)
            return;

        const int WM_KEYDOWN = 0x100;
        const int WM_ENTERIDLE = 0x121;
        const int VK_DELETE = 0x2e;

        bool delete = m.Msg == WM_KEYDOWN && (int)m.WParam == VK_DELETE;
        if ((m.Msg == WM_KEYDOWN && !delete) || m.Msg == WM_ENTERIDLE)
        {
            DontProcessMessage(() =>
            {
                _validText = Text;
                _selectionStart = SelectionStart;
                _selectionEnd = SelectionLength;
            });
        }

        const int WM_CHAR = 0x102;
        const int WM_PASTE = 0x302;
        if (m.Msg == WM_CHAR || m.Msg == WM_PASTE || delete)
        {
            string newText = null;
            DontProcessMessage(() =>
            {
                newText = Text;
            });

            var e = new TextValidatingEventArgs(newText);
            OnTextValidating(this, e);
            if (e.Cancel)
            {
                DontProcessMessage(() =>
                {
                    Text = _validText;
                    SelectionStart = _selectionStart;
                    SelectionLength = _selectionEnd;
                });
            }
        }
    }

    private void DontProcessMessage(Action action)
    {
        _dontProcessMessages = true;
        try
        {
            action();
        }
        finally
        {
            _dontProcessMessages = false;
        }
    }
}

public class TextValidatingEventArgs : CancelEventArgs
{
    public TextValidatingEventArgs(string newText) => NewText = newText;
    public string NewText { get; }
}

对于Int32，您可以从中派生出来，如下所示：

public class Int32TextBox : ValidatingTextBox
{
    protected override void OnTextValidating(object sender, TextValidatingEventArgs e)
    {
        e.Cancel = !int.TryParse(e.NewText, out int i);
    }
}

或w / o派生，使用新的TextValidating事件，如下所示：

var vtb = new ValidatingTextBox();
...
vtb.TextValidating += (sender, e) => e.Cancel = !int.TryParse(e.NewText, out int i);

但是它很好用于任何字符串和任何验证例程。

Answer 5

这正是验证/验证事件的设计目的。

以下是关于该主题的MSDN文章：http://msdn.microsoft.com/en-us/library/system.windows.forms.control.validating.aspx

TL; DR版本：检查Validating事件中的.Text属性，并在数据无效时设置e.Cancel=True。

当您设置e.Cancel = True时，用户无法离开该字段，但您需要向他们提供某种错误的反馈。我将框的背景颜色更改为浅红色以指示问题。当使用一个好的值调用Validating时，请务必将其设置回SystemColors.Window。

Answer 6

尝试MaskedTextBox。它采用简单的掩码格式，因此您可以将输入限制为数字或日期等等。

Answer 7

您可以使用TextChanged事件

private void textBox_BiggerThan_TextChanged(object sender, EventArgs e)
{
    long a;
    if (! long.TryParse(textBox_BiggerThan.Text, out a))
    {
        // If not int clear textbox text or Undo() last operation
        textBox_LessThan.Clear();
    }
}

Answer 8

我一直在研究一系列组件来完成WinForms中缺少的东西，这里是：Advanced Forms

特别是这是Regex TextBox的类

/// <summary>Represents a Windows text box control that only allows input that matches a regular expression.</summary>
public class RegexTextBox : TextBox
{
    [NonSerialized]
    string lastText;

    /// <summary>A regular expression governing the input allowed in this text field.</summary>
    [Browsable(false), EditorBrowsable(EditorBrowsableState.Never)]
    [DesignerSerializationVisibility(DesignerSerializationVisibility.Hidden)]
    public virtual Regex Regex { get; set; }

    /// <summary>A regular expression governing the input allowed in this text field.</summary>
    [DefaultValue(null)]
    [Category("Behavior")]
    [Description("Sets the regular expression governing the input allowed for this control.")]
    public virtual string RegexString {
        get {
            return Regex == null ? string.Empty : Regex.ToString();
        }
        set {
            if (string.IsNullOrEmpty(value))
                Regex = null;
            else
                Regex = new Regex(value);
        }
    }

    protected override void OnTextChanged(EventArgs e) {
        if (Regex != null && !Regex.IsMatch(Text)) {
            int pos = SelectionStart - Text.Length + (lastText ?? string.Empty).Length;
            Text = lastText;
            SelectionStart = Math.Max(0, pos);
        }

        lastText = Text;

        base.OnTextChanged(e);
    }
}

只需添加myNumbericTextBox.RegexString = "^(\\d+|)$";等内容即可。

Answer 9

这可能很有用。它允许“实际”数值，包括正确的小数点和前面的加号或减号。在相关的KeyPress事件中调用它。

       private bool IsOKForDecimalTextBox(char theCharacter, TextBox theTextBox)
    {
        // Only allow control characters, digits, plus and minus signs.
        // Only allow ONE plus sign.
        // Only allow ONE minus sign.
        // Only allow the plus or minus sign as the FIRST character.
        // Only allow ONE decimal point.
        // Do NOT allow decimal point or digits BEFORE any plus or minus sign.

        if (
            !char.IsControl(theCharacter)
            && !char.IsDigit(theCharacter)
            && (theCharacter != '.')
            && (theCharacter != '-')
            && (theCharacter != '+')
        )
        {
            // Then it is NOT a character we want allowed in the text box.
            return false;
        }



        // Only allow one decimal point.
        if (theCharacter == '.'
            && theTextBox.Text.IndexOf('.') > -1)
        {
            // Then there is already a decimal point in the text box.
            return false;
        }

        // Only allow one minus sign.
        if (theCharacter == '-'
            && theTextBox.Text.IndexOf('-') > -1)
        {
            // Then there is already a minus sign in the text box.
            return false;
        }

        // Only allow one plus sign.
        if (theCharacter == '+'
            && theTextBox.Text.IndexOf('+') > -1)
        {
            // Then there is already a plus sign in the text box.
            return false;
        }

        // Only allow one plus sign OR minus sign, but not both.
        if (
            (
                (theCharacter == '-')
                || (theCharacter == '+')
            )
            && 
            (
                (theTextBox.Text.IndexOf('-') > -1)
                ||
                (theTextBox.Text.IndexOf('+') > -1)
            )
            )
        {
            // Then the user is trying to enter a plus or minus sign and
            // there is ALREADY a plus or minus sign in the text box.
            return false;
        }

        // Only allow a minus or plus sign at the first character position.
        if (
            (
                (theCharacter == '-')
                || (theCharacter == '+')
            )
            && theTextBox.SelectionStart != 0
            )
        {
            // Then the user is trying to enter a minus or plus sign at some position 
            // OTHER than the first character position in the text box.
            return false;
        }

        // Only allow digits and decimal point AFTER any existing plus or minus sign
        if  (
                (
                    // Is digit or decimal point
                    char.IsDigit(theCharacter)
                    ||
                    (theCharacter == '.')
                )
                &&
                (
                    // A plus or minus sign EXISTS
                    (theTextBox.Text.IndexOf('-') > -1)
                    ||
                    (theTextBox.Text.IndexOf('+') > -1)
                )
                &&
                    // Attempting to put the character at the beginning of the field.
                    theTextBox.SelectionStart == 0
            )
        {
            // Then the user is trying to enter a digit or decimal point in front of a minus or plus sign.
            return false;
        }

        // Otherwise the character is perfectly fine for a decimal value and the character
        // may indeed be placed at the current insertion position.
        return true;
    }

Answer 10

只需在文本框中使用此代码：

private void textBox1_TextChanged(object sender, EventArgs e)
{

    double parsedValue;

    if (!double.TryParse(textBox1.Text, out parsedValue))
    {
        textBox1.Text = "";
    }
}

Answer 11

在我们的带有文本框定义的网页中，我们可以添加onkeypress事件来仅接受数字。它不会显示任何消息，但会阻止您输入错误信息。它对我有用，除了数字之外，用户无法输入任何内容。

<asp:TextBox runat="server" ID="txtFrom"
     onkeypress="if(isNaN(String.fromCharCode(event.keyCode))) return false;">

Answer 12

只需使用NumericUpDown控件，并将那些丑陋的按钮可见性设置为false。

numericUpDown1.Controls[0].Visible = false;

NumericUpDown实际上是一个控件集合，其中包含一个＆＃39;旋转框＆＃39; （向上按下按钮），一个文本框和一些代码来验证和混合它们。

标志：

YourNumericUpDown.Controls[0].visible = false

将隐藏按钮，同时保持底层代码处于活动状态。

虽然不是一个明显的解决方案，但它简单有效。如果你想这样做，.Controls[1]会隐藏文本框部分。

Answer 13

我已在CodePlex上为此做了一些事情。

它通过拦截TextChanged事件来工作。如果结果是一个好的数字，它将被存储。如果出现问题，将恢复最后一个好的值。源代码太大而无法在此处发布，但here is a link to the class处理此逻辑的核心。

Answer 14

需要接受整数和浮点数，包括负数。

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    // Text
    string text = ((Control) sender).Text;

    // Is Negative Number?
    if (e.KeyChar == '-' && text.Length == 0)
    {
        e.Handled = false;
        return;
    }

    // Is Float Number?
    if (e.KeyChar == '.' && text.Length > 0 && !text.Contains("."))
    {
        e.Handled = false;
        return;
    }

    // Is Digit?
    e.Handled = (!char.IsDigit(e.KeyChar) && !char.IsControl(e.KeyChar));
}

Answer 15

使用Fabio Iotti's answer中描述的方法，我创建了一个更通用的解决方案：

public abstract class ValidatedTextBox : TextBox {
    private string m_lastText = string.Empty;
    protected abstract bool IsValid(string text);
    protected sealed override void OnTextChanged(EventArgs e) {
        if (!IsValid(Text)) {
            var pos = SelectionStart - Text.Length + m_lastText.Length;
            Text = m_lastText;
            SelectionStart = Math.Max(0, pos);
        }
        m_lastText = Text;
        base.OnTextChanged(e);
    }
}

“ValidatedTextBox”，包含所有重要的验证行为。剩下要做的就是从这个类继承，并使用任何需要的验证逻辑覆盖“IsValid”方法。例如，使用此类，可以创建“RegexedTextBox”，它只接受与特定正则表达式匹配的字符串：

public abstract class RegexedTextBox : ValidatedTextBox {
    private readonly Regex m_regex;
    protected RegexedTextBox(string regExpString) {
        m_regex = new Regex(regExpString);
    }
    protected override bool IsValid(string text) {
        return m_regex.IsMatch(Text);
    }
}

之后，继承自“RegexedTextBox”类，我们可以轻松创建“PositiveNumberTextBox”和“PositiveFloatingPointNumberTextBox”控件：

public sealed class PositiveNumberTextBox : RegexedTextBox {
    public PositiveNumberTextBox() : base(@"^\d*$") { }
}

public sealed class PositiveFloatingPointNumberTextBox : RegexedTextBox {
    public PositiveFloatingPointNumberTextBox()
        : base(@"^(\d+\" + CultureInfo.CurrentCulture.NumberFormat.NumberDecimalSeparator + @")?\d*$") { }
}

Answer 16

您可以使用TextChanged / Keypress事件，使用正则表达式对数字进行过滤并采取一些措施。

Answer 17

private void txt3_KeyPress(object sender, KeyPressEventArgs e)
{
    for (int h = 58; h <= 127; h++)
    {
        if (e.KeyChar == h)             //58 to 127 is alphabets tat will be         blocked
        {
            e.Handled = true;
        }
    }
    for(int k=32;k<=47;k++)
    {
        if (e.KeyChar == k)              //32 to 47 are special characters tat will 
        {                                  be blocked
            e.Handled = true;
        }
    }
}

试试这很简单

Answer 18

您好，您可以在文本框的textchanged事件中执行此类操作。

这是一个演示

    private void textBox1_TextChanged(object sender, EventArgs e)
    {
        string actualdata = string.Empty;
        char[] entereddata = textBox1.Text.ToCharArray();
        foreach (char aChar in entereddata.AsEnumerable())
        {
            if (Char.IsDigit(aChar))
            {
                actualdata = actualdata + aChar;
                // MessageBox.Show(aChar.ToString());
            }
            else
            {
                MessageBox.Show(aChar + " is not numeric");
                actualdata.Replace(aChar, ' ');
                actualdata.Trim();
            }
        }
        textBox1.Text = actualdata;
    }

Answer 19

查看Input handling in WinForm

我发布了我的解决方案，该解决方案使用文本框上的ProcessCmdKey和OnKeyPress事件。评论向您展示了如何使用正则表达式来验证按键和正确阻止/允许。

Answer 20

似乎这个问题的许多当前答案都是手动解析输入文本。如果您正在寻找特定的内置数字类型（例如int或double），为什么不将该工作委托给该类型的TryParse方法呢？例如：

public class IntTextBox : TextBox
{
    string PreviousText = "";
    int BackingResult;

    public IntTextBox()
    {
        TextChanged += IntTextBox_TextChanged;
    }

    public bool HasResult { get; private set; }

    public int Result
    {
        get
        {
            return HasResult ? BackingResult : default(int);
        }
    }

    void IntTextBox_TextChanged(object sender, EventArgs e)
    {
        HasResult = int.TryParse(Text, out BackingResult);

        if (HasResult || string.IsNullOrEmpty(Text))
        {
            // Commit
            PreviousText = Text;
        }
        else
        {
            // Revert
            var changeOffset = Text.Length - PreviousText.Length;
            var previousSelectionStart =
                Math.Max(0, SelectionStart - changeOffset);

            Text = PreviousText;
            SelectionStart = previousSelectionStart;
        }
    }
}

如果您想要更通用但仍与Visual Studio的Designer兼容的东西：

public class ParsableTextBox : TextBox
{
    TryParser BackingTryParse;
    string PreviousText = "";
    object BackingResult;

    public ParsableTextBox()
        : this(null)
    {
    }

    public ParsableTextBox(TryParser tryParse)
    {
        TryParse = tryParse;

        TextChanged += ParsableTextBox_TextChanged;
    }

    public delegate bool TryParser(string text, out object result);

    public TryParser TryParse
    {
        set
        {
            Enabled = !(ReadOnly = value == null);

            BackingTryParse = value;
        }
    }

    public bool HasResult { get; private set; }

    public object Result
    {
        get
        {
            return GetResult<object>();
        }
    }

    public T GetResult<T>()
    {
        return HasResult ? (T)BackingResult : default(T);
    }

    void ParsableTextBox_TextChanged(object sender, EventArgs e)
    {
        if (BackingTryParse != null)
        {
            HasResult = BackingTryParse(Text, out BackingResult);
        }

        if (HasResult || string.IsNullOrEmpty(Text))
        {
            // Commit
            PreviousText = Text;
        }
        else
        {
            // Revert
            var changeOffset = Text.Length - PreviousText.Length;
            var previousSelectionStart =
                Math.Max(0, SelectionStart - changeOffset);

            Text = PreviousText;
            SelectionStart = previousSelectionStart;
        }
    }
}

最后，如果你想要一些完全通用的东西并且不关心Designer支持：

public class ParsableTextBox<T> : TextBox
{
    TryParser BackingTryParse;
    string PreviousText;
    T BackingResult;

    public ParsableTextBox()
        : this(null)
    {
    }

    public ParsableTextBox(TryParser tryParse)
    {
        TryParse = tryParse;

        TextChanged += ParsableTextBox_TextChanged;
    }

    public delegate bool TryParser(string text, out T result);

    public TryParser TryParse
    {
        set
        {
            Enabled = !(ReadOnly = value == null);

            BackingTryParse = value;
        }
    }

    public bool HasResult { get; private set; }

    public T Result
    {
        get
        {
            return HasResult ? BackingResult : default(T);
        }
    }

    void ParsableTextBox_TextChanged(object sender, EventArgs e)
    {
        if (BackingTryParse != null)
        {
            HasResult = BackingTryParse(Text, out BackingResult);
        }

        if (HasResult || string.IsNullOrEmpty(Text))
        {
            // Commit
            PreviousText = Text;
        }
        else
        {
            // Revert
            var changeOffset = Text.Length - PreviousText.Length;
            var previousSelectionStart =
                Math.Max(0, SelectionStart - changeOffset);

            Text = PreviousText;
            SelectionStart = previousSelectionStart;
        }
    }
}

Answer 21

不要忘记用户可以在TextBox中粘贴无效文字。

如果您想限制，请按照以下代码：

private void ultraTextEditor1_TextChanged(object sender, EventArgs e)
{
    string append="";
    foreach (char c in ultraTextEditor1.Text)
    {
        if ((!Char.IsNumber(c)) && (c != Convert.ToChar(Keys.Back)))
        {

        }
        else
        {
            append += c;
        }
    }

    ultraTextEditor1.Text = append;
}

Answer 22

我也在寻找最好的方法来检查文本框中的数字和keypress的问题是因为它不支持通过右键单击或剪贴板复制粘贴所以想出了这个代码，它验证了光标离开文本字段的时间以及它检查空场。（改编版的newguy）

private void txtFirstValue_MouseLeave(object sender, EventArgs e)
{
    int num;
    bool isNum = int.TryParse(txtFirstValue.Text.Trim(), out num);

    if (!isNum && txtFirstValue.Text != String.Empty)
    {
        MessageBox.Show("The First Value You Entered Is Not a Number, Please Try Again", "Invalid Value Detected", MessageBoxButtons.OK, MessageBoxIcon.Error);
        txtFirstValue.Clear();
    }
}

Answer 23

这是使用 .NET 5/Core 做到这一点的好方法

 private void textBox1_KeyDown(object sender, KeyEventArgs e)
        {
            e.SuppressKeyPress = !int.TryParse(Convert.ToString((char)e.KeyData), out int _result);
        }

Answer 24

很抱歉唤醒死者，但我认为有人可能会发现这对将来有用。

这是我如何处理它。它处理浮点数，但可以很容易地修改为整数。

基本上你只能按 0 - 9 和。

之前只能有一个 0 。

忽略所有其他字符并保持光标位置。

    private bool _myTextBoxChanging = false;

    private void myTextBox_TextChanged(object sender, EventArgs e)
    {
        validateText(myTextBox);
    }

    private void validateText(TextBox box)
    {
        // stop multiple changes;
        if (_myTextBoxChanging)
            return;
        _myTextBoxChanging = true;

        string text = box.Text;
        if (text == "")
            return;
        string validText = "";
        bool hasPeriod = false;
        int pos = box.SelectionStart;
        for (int i = 0; i < text.Length; i++ )
        {
            bool badChar = false;
            char s = text[i];
            if (s == '.')
            {
                if (hasPeriod)
                    badChar = true;
                else
                    hasPeriod = true;
            }
            else if (s < '0' || s > '9')
                badChar = true;

            if (!badChar)
                validText += s;
            else
            {
                if (i <= pos)
                    pos--;
            }
        }

        // trim starting 00s
        while (validText.Length >= 2 && validText[0] == '0')
        {
            if (validText[1] != '.')
            {
                validText = validText.Substring(1);
                if (pos < 2)
                    pos--;
            }
            else
                break;
        }

        if (pos > validText.Length)
            pos = validText.Length;
        box.Text = validText;
        box.SelectionStart = pos;
        _myTextBoxChanging = false;
    }

这是一个快速修改的int版本：

    private void validateText(TextBox box)
    {
        // stop multiple changes;
        if (_myTextBoxChanging)
            return;
        _myTextBoxChanging = true;

        string text = box.Text;
        if (text == "")
            return;
        string validText = "";
        int pos = box.SelectionStart;
        for (int i = 0; i < text.Length; i++ )
        {
            char s = text[i];
            if (s < '0' || s > '9')
            {
                if (i <= pos)
                    pos--;
            }
            else
                validText += s;
        }

        // trim starting 00s 
        while (validText.Length >= 2 && validText.StartsWith("00")) 
        { 
            validText = validText.Substring(1); 
            if (pos < 2) 
                pos--; 
        } 

        if (pos > validText.Length)
            pos = validText.Length;
        box.Text = validText;
        box.SelectionStart = pos;
        _myTextBoxChanging = false;
    }

Answer 25

这个可以复制和粘贴，拖放，按键，防止溢出，非常简单

public partial class IntegerBox : TextBox 
{
    public IntegerBox()
    {
        InitializeComponent();
        this.Text = 0.ToString();
    }

    protected override void OnPaint(PaintEventArgs pe)
    {
        base.OnPaint(pe);
    }

    private String originalValue = 0.ToString();

    private void Integerbox_KeyPress(object sender, KeyPressEventArgs e)
    {
        originalValue = this.Text;
    }

    private void Integerbox_TextChanged(object sender, EventArgs e)
    {
        try
        {
            if(String.IsNullOrWhiteSpace(this.Text))
            {
                this.Text = 0.ToString();
            }
            this.Text = Convert.ToInt64(this.Text.Trim()).ToString();
        }
        catch (System.OverflowException)
        {
            MessageBox.Show("Value entered is to large max value: " + Int64.MaxValue.ToString(), "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
            this.Text = originalValue;
        }
        catch (System.FormatException)
        {                
            this.Text = originalValue;
        }
        catch (System.Exception ex)
        {
            this.Text = originalValue;
            MessageBox.Show(ex.Message, "Error", MessageBoxButtons.OK , MessageBoxIcon.Error);
        }
    }       
}

Answer 26

我会在KeyDown事件中处理它。

void TextBox_KeyDown(object sender, KeyEventArgs e)
        {
            char c = Convert.ToChar(e.PlatformKeyCode);
            if (!char.IsDigit(c))
            {
                e.Handled = true;
            }
        }

Answer 27

我为各种验证创建了一个可重用的文本框扩展类，并考虑过分享它。

您需要做的就是引发 TextChange事件，然后调用Validate方法。它看起来像这样：

private void tbxAmount_TextChanged(object sender, EventArgs e)
{ 
    tbxAmount.Validate(TextValidator.ValidationType.Amount);
}

这是扩展类：

public static class TextValidator
{
    public enum ValidationType
    {
        Amount,
        Integer
    }

    /// <summary>
    /// Validate a textbox on text change.
    /// </summary>
    /// <param name="tbx"></param>
    /// <param name="validationType"></param>
    public static void Validate(this TextBox tbx, ValidationType validationType)
    {
        PerformValidation(tbx, validationType);
        tbx.Select(tbx.Text.Length, 0);
    }


    private static void PerformValidation(this TextBox tbx, ValidationType validationType)
    {
        char[] enteredString = tbx.Text.ToCharArray();
        switch (validationType)
        {
            case ValidationType.Amount:
                tbx.Text = AmountValidation(enteredString);
                break;

            case ValidationType.Integer:
                tbx.Text = IntegerValidation(enteredString);
                break;

            default:
                break;
        }

        tbx.SelectionStart = tbx.Text.Length;
    }



    private static string AmountValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        int count = 0;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (count >= 1 && c == '.')
            { actualString.Replace(c, ' '); actualString.Trim(); }
            else
            {
                if (Char.IsDigit(c))
                {
                    actualString = actualString + c;
                }

                if (c == '.')
                {
                    actualString = actualString + c; count++;
                }

                else
                {
                    actualString.Replace(c, ' ');
                    actualString.Trim();
                }
            }
        }
        return actualString;
    }


    private static string IntegerValidation(char[] enteredString)
    {
        string actualString = string.Empty;
        foreach (char c in enteredString.AsEnumerable())
        {
            if (Char.IsDigit(c))
            {
                actualString = actualString + c;
            }
            else
            {
                actualString.Replace(c, ' ');
                actualString.Trim();
            }
        }
        return actualString;
    }
}

You can find the full code here

Answer 28

最简单，最粗糙的方法是使用组合框而不是带有ReadOnly的文本框。但是，当然只有在期望用户使用一套体面且合理的整数而不是尝试无穷大时，它才有用。

Answer 29

这里有30多个答案，很多答案都很有帮助。但我想共享 System.Windows.Forms.TextBox 和 System.Windows.Controls.TextBox 的通用形式。

System.Windows.Controls.TextBox 中没有可用的 KeyPress 事件。该答案适用于那些希望对 System.Windows.Forms.TextBox 和 System.Windows.Controls.TextBox 使用相同逻辑的人。

这是 NumberTextBox 代码。 System.Windows.Controls.TextBox 使用注释行代替上一行。

public class NumberTextBox : System.Windows.Forms.TextBox
//public class NumberTextBox : System.Windows.Controls.TextBox
{
    private double _maxValue;
    private double _minValue;
    private bool _flag;
    private string _previousValue;

    public NumberTextBox()
    {
        this.TextAlign = HorizontalAlignment.Right;
        //TextAlignment = TextAlignment.Right;
        KeyDown += TextBox_KeyDown;
        TextChanged += TextBox_TextChanged;
        _minValue = double.MinValue;
        _maxValue = double.MaxValue;
    }

    private void TextBox_KeyDown(object sender, KeyEventArgs e)
    {
        _previousValue = this.Text;
        _flag = this.SelectedText.Length > 0;
    }

    private void TextBox_TextChanged(object sender, EventArgs e)
    //private void TextBox_TextChanged(object sender, TextChangedEventArgs e)
    {
        var text = this.Text;
        if (text.Length < 1) return;
        var cursorPosition = SelectionStart == 0 ? SelectionStart : SelectionStart - 1;
        var insertedChar = text[cursorPosition];
        if (IsInvalidInput(insertedChar, cursorPosition, text))
        {
            HandleText(text, cursorPosition);
        }
        ValidateRange(text, cursorPosition);
    }

    private bool IsInvalidInput(char insertedChar, int cursorPosition, string text)
    {
        return !char.IsDigit(insertedChar) && insertedChar != '.' && insertedChar != '-' ||
               insertedChar == '-' && cursorPosition != 0 ||
               text.Count(x => x == '.') > 1 ||
               text.Count(x => x == '-') > 1;
    }

    private void HandleText(string text, int cursorPosition)
    {
        this.Text = _flag ? _previousValue : text.Remove(cursorPosition, 1);
        this.SelectionStart = cursorPosition;
        this.SelectionLength = 0;
    }

    private void ValidateRange(string text, int cursorPosition)
    {
        try
        {
            if (text == "." || _minValue < 0 && text == "-") return;
            var doubleValue = Convert.ToDouble(text);
            if (doubleValue > _maxValue || doubleValue < _minValue)
            {
                HandleText(text, cursorPosition);
            }
        }
        catch (Exception)
        {
            HandleText(text, cursorPosition);
        }
    }

    protected void SetProperties(double minValue = double.MinValue, double maxValue = double.MaxValue)
    {
        _minValue = minValue;
        _maxValue = maxValue;
    }       

}

PositiveNumberTextBox 代码：

public class PositiveNumberTextBox : NumberTextBox
{
    public PositiveNumberTextBox()
    {
        SetProperties(0);
    }
}

FractionNumberTextBox 代码：

public class FractionNumberTextBox : NumberTextBox
{
    public FractionNumberTextBox()
    {
        SetProperties(0, 0.999999);
    }
}

Answer 30

使用RegularExpressionValidator：

<asp:TextBox ID="TextBoxNum" runat="server"></asp:TextBox><br />
<asp:RegularExpressionValidator ID="RegularExpressionValidator1"
                        ControlToValidate="TextBoxNum" runat="server"
                        ErrorMessage="Only numbers allowed"
                        ValidationExpression="\d+">
</asp:RegularExpressionValidator>

Answer 31

您可以通过此简单代码简单地阻止添加非数字字符

 if (long.TryParse(TextBox.Text,out long isparsable))
        {
          // your code to handle numbers
        }
        else
        {
            TextBox.Text="Only Numbers Allowed";
            TextBox.Focus();
            TextBox.SelectAll();
        }

Answer 32

适用于WPF和简单的TextChangedEventArgs的工作解决方案。

private void TextBox_TextChanged(object sender, TextChangedEventArgs e)
{
    var TextBox = (sender as TextBox);

    // if not a numeric value, remove news characters
    if (Regex.IsMatch(TextBox.Text, "[^0-9]"))
    {
        foreach (TextChange Change in e.Changes)
        {
            TextBox.Text = TextBox.Text.Remove(Change.Offset, Change.AddedLength);

            TextBox.CaretIndex = Change.Offset;
        }
    }
}

Answer 33

int Number;
bool isNumber;
isNumber = int32.TryPase(textbox1.text, out Number);

if (!isNumber)
{ 
    (code if not an integer);
}
else
{
    (code if an integer);
}

Answer 34

这是我的理由：

使用linq（易于修改过滤器）
复制/粘贴验证码
按下禁止的字符时保持插入位置
接受左零

以及任何大小的数字

private void numeroCuenta_TextChanged(object sender, EventArgs e)
{
    string org = numeroCuenta.Text;
    string formated = string.Concat(org.Where(c => (c >= '0' && c <= '9')));
    if (formated != org)
    {
        int s = numeroCuenta.SelectionStart;
        if (s > 0 && formated.Length > s && org[s - 1] != formated[s - 1]) s--;
        numeroCuenta.Text = formated;
        numeroCuenta.SelectionStart = s;
    }
}

Answer 35

FAIL-SAFE ，简单＆＃34;递归＆＃34;方法，可以与多个文本框一起使用。

它会阻止错误的键盘输入字符以及粘贴的值等。它只接受整数，而最大数字长度是字符串类型的最大长度（这是int，真的很长！）

public void Check_If_Int_On_TextChanged(object sender, EventArgs e)
{
   // This method checks that each inputed character is a number. Any non-numeric
   // characters are removed from the text

   TextBox textbox = (TextBox)sender;

   // If the text is empty, return
   if (textbox.Text.Length == 0) { return; }

   // Check the new Text value if it's only numbers
   byte parsedValue;
   if (!byte.TryParse(textbox.Text[(textbox.Text.Length - 1)].ToString(), out parsedValue))
   {
      // Remove the last character as it wasn't a number
      textbox.Text = textbox.Text.Remove((textbox.Text.Length - 1));

      // Move the cursor to the end of text
      textbox.SelectionStart = textbox.Text.Length;
    }
 }

Answer 36

3解决方案

1）

//Add to the textbox's KeyPress event
//using Regex for number only textBox

private void txtBox_KeyPress(object sender, KeyPressEventArgs e)
{
if (!System.Text.RegularExpressions.Regex.IsMatch(e.KeyChar.ToString(), "\\d+"))
e.Handled = true;
}

2）来自msdn的另一个解决方案

// Boolean flag used to determine when a character other than a number is entered.
private bool nonNumberEntered = false;
// Handle the KeyDown event to determine the type of character entered into the     control.
private void textBox1_KeyDown(object sender, KeyEventArgs e)
{
// Initialize the flag to false.
nonNumberEntered = false;
// Determine whether the keystroke is a number from the top of the keyboard.
if (e.KeyCode < Keys.D0 || e.KeyCode > Keys.D9)
{
    // Determine whether the keystroke is a number from the keypad.
    if (e.KeyCode < Keys.NumPad0 || e.KeyCode > Keys.NumPad9)
    {
        // Determine whether the keystroke is a backspace.
        if (e.KeyCode != Keys.Back)
        {
            // A non-numerical keystroke was pressed.
            // Set the flag to true and evaluate in KeyPress event.
            nonNumberEntered = true;
        }
    }
}

}

private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
    if (nonNumberEntered == true)
    {
       MessageBox.Show("Please enter number only..."); 
       e.Handled = true;
    }
}

来源http://msdn.microsoft.com/en-us/library/system.windows.forms.control.keypress(v=VS.90).aspx

3）使用MaskedTextBox：http://msdn.microsoft.com/en-us/library/system.windows.forms.maskedtextbox.aspx

Answer 37

在按钮单击中，您可以通过for循环检查文本框的文本：

char[] c = txtGetCustomerId.Text.ToCharArray();
bool IsDigi = true;

for (int i = 0; i < c.Length; i++)
     {
       if (c[i] < '0' || c[i] > '9')
      { IsDigi = false; }
     }
 if (IsDigi)
    { 
     // do something
    }

Answer 38

更简单的回答：

_textBox.TextChanged += delegate(System.Object o, System.EventArgs e)
{
    TextBox _tbox = o as TextBox;
    _tbox.Text = new string(_tbox.Text.Where(c => (char.IsDigit(c)) || (c == '.')).ToArray());
};

Answer 39

我喜欢简洁的代码

    private void xmm_textbox_KeyPress(object sender, KeyPressEventArgs e) {
        double x;
        e.Handled = !double.TryParse(((TextBox)sender).Text, out x);
    }

如何制作仅接受数字的文本框？

40 个答案: