我正在开发一款Xamarin.Android应用。我正在连接到Azure移动应用程序,我正在EasyTable中获取/存储数据。
现在这是我的用户'登录'和注册的代码。这只是测试查询,所以不要介意明显不安全的登录:
public async Task Initialize()
{
MobileService = new MobileServiceClient(myappwebsiteinazurestring);
string path = Path.Combine(MobileServiceClient.DefaultDatabasePath, "UserSync.db");
var store = new MobileServiceSQLiteStore(path);
store.DefineTable<Users_Table>();
await MobileService.SyncContext.InitializeAsync(store, new MobileServiceSyncHandler());
userTable = MobileService.GetSyncTable<Users_Table>();
}
public async Task SyncUsers()
{
await userTable.PullAsync("Users_Table", userTable.CreateQuery());
await MobileService.SyncContext.PushAsync();
}
public async Task<List<Users_Table>> loginUser(string username, string password)
{
List<Users_Table> userLogin = await userTable
.Where(user => user.Username == username && user.Password == password)
.ToListAsync();
await MobileService.SyncContext.PushAsync();
return userLogin;
}
这是登录和初始化。现在这里是注册部分:
public async Task AddUser(Users_Table user)
{
var InsUser = new Users_Table
{
Name = user.Name,
Username = user.Username,
Password = user.Password,
LicensePlate = user.LicensePlate,
Email = user.Email,
Exp = user.Exp
};
await userTable.InsertAsync(InsUser);
await SyncUsers();
}
现在这很好。这是我从我的应用程序中调用它们的方式:
private async void LoginButton_Click(object sender, EventArgs e)
{
EditText username = FindViewById<EditText>(Resource.Id.LoginEditTextUsername);
EditText password = FindViewById<EditText>(Resource.Id.LoginEditTextPassword);
var prog = new ProgressDialog(this);
prog.SetMessage("Logging in...");
prog.Show();
AzureDataService az = new AzureDataService();
List<Users_Table> user = new List<Users_Table>();
try
{
await az.Initialize();
user = await az.loginUser(username.Text, password.Text);
}
catch (Exception ex)
{
Toast.MakeText(this.ApplicationContext, "Error: " + ex.Message + "\n" + ex.Source, ToastLength.Long).Show();
return;
}
注册:
private async void CreateProfile()
{
EditText regUsername = FindViewById<EditText>(Resource.Id.RegisterLayoutUsername);
EditText regPassword = FindViewById<EditText>(Resource.Id.RegisterLayoutPassword);
EditText regConfirmPassword = FindViewById<EditText>(Resource.Id.RegisterLayoutConfirmPassword);
EditText regPlateNumber = FindViewById<EditText>(Resource.Id.RegisterLayoutPlateNumber);
EditText regEmail = FindViewById<EditText>(Resource.Id.RegisterLayoutEmail);
EditText regName = FindViewById<EditText>(Resource.Id.RegisterLayoutName);
var user = new Users_Table
{
Username = regUsername.Text,
Password = regPassword.Text,
LicensePlate = parseLicensePlate(regPlateNumber.Text),
Name = regName.Text,
Email = regEmail.Text,
Exp = 0
};
try
{
var pd = new ProgressDialog(this);
pd.SetMessage("Creating Profile...");
pd.Show();
AzureDataService az = new AzureDataService();
await az.Initialize();
await az.AddUser(user);
pd.Dismiss();
}
一旦我在任何带有apk的设备上进行测试,登录就会失败。该应用程序收到null Users_Table,因此显示用户名/密码不正确的消息。
然而奇怪的是:寄存器没有任何问题。一旦我成功注册了新用户,对于现有用户和新创建的用户,登录也会通过。这就像在register方法中发生的事情一样,可以启动与任何事物的连接。
有没有人经历过这个?发生了什么事?
答案 0 :(得分:0)
我通过在任何进程之前添加syncusers()来实现它的工作,例如这样登录:
public async Task<List<Users_Table>> loginUser(string username, string password)
{
await SyncUsers();//here
List<Users_Table> userLogin = await userTable
.Where(user => user.Username == username && user.Password == password)
.ToListAsync();
await MobileService.SyncContext.PushAsync();
return userLogin;
}