Question

我在这个SQL中查询了数据：

//query by location total post
$sql = 'SELECT ljj.job_id, count(ljj.job_id) as count, ljj.job_type FROM {local_jobs_job} ljj INNER JOIN {local_jobs_location} ljl ON ljj.job_location = ljl.location_id GROUP BY ljj.job_type';


//get the query into record
$data = $DB->get_records_sql($sql);

输出在这里：

Array ( [1] => stdClass Object ( [job_id] => 1 [count] => 8 [job_type] => 0 ) [3] => stdClass Object ( [job_id] => 3 [count] => 7 [job_type] => 1 ) )

我需要更改：

的值

[job_type] => 0 to [job_type] => 'Job' 
[job_type] => 1 to [job_type] => 'Internship'

我不知道如何获取该值，因为它是一个对象数组。

如何获取值并替换它？

Answer 1

这里有一个基于你的例子的complet：所以你在输出中得到了一些 3个数组 第一个数组添加 2个子对象 索引1,3 < em> childs对象得到一个包含3个索引文字的数组（ job_id，count，job_type ），所以 array = [] 和< strong> object = {}

所以我施放对象（对象） 2子阵列和转换到对象一个 stdclass对象作为从数据库获取的示例。

<?php
//Array ( [1] => stdClass Object ( [job_id] => 1 [count] => 8 [job_type] => 0 ) [3] => stdClass Object ( [job_id] => 3 [count] => 7 [job_type] => 1 ) );

$data = Array( 1=>(object)Array("job_id" => 1, "count" => 8, "job_type" => 0), 3 => (object)Array("job_id" => 3, "count" => 7, "job_type" => 1));


var_dump($data); // show your ouput

var_dump($data[1]->{'job_type'}); // index 1 to object attribute job_type = we got the value  "0"
var_dump($data[3]->{'job_id'}); // index 3 to object attribute job_type = value = "1"

//to change you have to affect your value so :
$data[1]->{'job_type'} = "Job";
$data[3]->{'job_type'} = "Internship";

var_dump($data[1]->{'job_type'}); // index 1 to object attribute job_type = we got the value  "job"
var_dump($data[3]->{'job_type'}); // index 3 to object attribute job_type = value = "Internship"

如何更改数组对象的值？

1 个答案: