Question

我在调试下面的get_secondary_connections功能时遇到问题。出于某种原因，我的for friend in network[user][‘connections’]循环始终停在列表中的第一个值，而不是循环遍历整个列表。我不明白为什么会这样。有人可以给我一些指导吗？非常感谢！

这是我的网络：

network = { 

'Freda': {'connections': ['Olive', 'John', 'Debra'], 'favorite games': ['Starfleet Commander', 'Ninja Hamsters', 'Seahorse Adventures']}, 

'Ollie': {'connections': ['Mercedes', 'Freda', 'Bryant'], 'favorite games': ['Call of Arms', 'Dwarves and Swords', 'The Movie: The Game']}, 

'Debra': {'connections': ['Walter', 'Levi', 'Jennie', 'Robin'], 'favorite games': ['Seven Schemers', 'Pirates in Java Island', 'Dwarves and Swords']}, 

'Olive': {'connections': ['John', 'Ollie'], 'favorite games': ['The Legend of Corgi', 'Starfleet Commander']}, 

'Levi': {'connections': ['Ollie', 'John', 'Walter'], 'favorite games': ['The Legend of Corgi', 'Seven Schemers', 'City Comptroller: The Fiscal Dilemma']}, 

'Jennie': {'connections': ['Levi', 'John', 'Freda', 'Robin'], 'favorite games': ['Super Mushroom Man', 'Dinosaur Diner', 'Call of Arms']}, 

'Mercedes': {'connections': ['Walter', 'Robin', 'Bryant'], 'favorite games': ['The Legend of Corgi', 'Pirates in Java Island', 'Seahorse Adventures']}, 

'John': {'connections': ['Bryant', 'Debra', 'Walter'], 'favorite games': ['The Movie: The Game', 'The Legend of Corgi', 'Dinosaur Diner']}, 

'Robin': {'connections': ['Ollie'], 'favorite games': ['Call of Arms', 'Dwarves and Swords']}, 

'Bryant': {'connections': ['Olive', 'Ollie', 'Freda', 'Mercedes'], 'favorite games': ['City Comptroller: The Fiscal Dilemma', 'Super Mushroom Man']},

'Walter': {'connections': ['John', 'Levi', 'Bryant'], 'favorite games': ['Seahorse Adventures', 'Ninja Hamsters', 'Super Mushroom Man']} }

这是我的代码：

def get_secondary_connections(network, user):
    if user not in network:
        return None
    sec_connections = []
    for friend in network[user]['connections']:
        for connection in network[friend]['connections']:
            if connection not in sec_connections:
                sec_connections.append(connection)
    return sec_connections

当我运行get_secondary_connections（网络，“Mercedes”）时，我得到以下输出：

[‘John’, ‘Levi’, ‘Bryant’]

如果您在我的网络上查看过，那么只有Walter的连接列表。我应该得到梅赛德斯的二级连接的完整列表，即：

[‘John’, ‘Levi’, ‘Bryant’, ‘Ollie’, ‘Olive’, Freda’, ‘Mercedes’]

有人可以帮帮我吗？

Answer 1

我复制粘贴您的代码并运行程序并获得输出：

['John', 'Levi', 'Bryant', 'Ollie', 'Olive', 'Freda', 'Mercedes']

这个输出是你想要的，对吗？您的代码没有任何问题。如果您愿意，这就是代码的外观：

network = {
'Freda': {'connections': ['Olive', 'John', 'Debra'], 'favorite games': ['Starfleet Commander', 'Ninja Hamsters', 'Seahorse Adventures']},

'Ollie': {'connections': ['Mercedes', 'Freda', 'Bryant'], 'favorite games': ['Call of Arms', 'Dwarves and Swords', 'The Movie: The Game']},

'Debra': {'connections': ['Walter', 'Levi', 'Jennie', 'Robin'], 'favorite games': ['Seven Schemers', 'Pirates in Java Island', 'Dwarves and Swords']},

'Olive': {'connections': ['John', 'Ollie'], 'favorite games': ['The Legend of Corgi', 'Starfleet Commander']},

'Levi': {'connections': ['Ollie', 'John', 'Walter'], 'favorite games': ['The Legend of Corgi', 'Seven Schemers', 'City Comptroller: The Fiscal Dilemma']},

'Jennie': {'connections': ['Levi', 'John', 'Freda', 'Robin'], 'favorite games': ['Super Mushroom Man', 'Dinosaur Diner', 'Call of Arms']},

'Mercedes': {'connections': ['Walter', 'Robin', 'Bryant'], 'favorite games': ['The Legend of Corgi', 'Pirates in Java Island', 'Seahorse Adventures']},

'John': {'connections': ['Bryant', 'Debra', 'Walter'], 'favorite games': ['The Movie: The Game', 'The Legend of Corgi', 'Dinosaur Diner']},

'Robin': {'connections': ['Ollie'], 'favorite games': ['Call of Arms', 'Dwarves and Swords']},

'Bryant': {'connections': ['Olive', 'Ollie', 'Freda', 'Mercedes'], 'favorite games': ['City Comptroller: The Fiscal Dilemma', 'Super Mushroom Man']},

'Walter': {'connections': ['John', 'Levi', 'Bryant'], 'favorite games': ['Seahorse Adventures', 'Ninja Hamsters', 'Super Mushroom Man']} 
}

def get_secondary_connections(network, user):
    if user not in network:
        return None
    sec_connections = []
    for friend in network[user]['connections']:
        for connection in network[friend]['connections']:
            if connection not in sec_connections:
                sec_connections.append(connection)
    return sec_connections

print get_secondary_connections(network, "Mercedes")

Python for循环在第一次迭代后停止

1 个答案: