Question

我正在尝试创建一个字典，其中的键将是预先存在的List<string>中的元素，值将为List<List<string>>，如下所示：

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();

Dictionary<string,List<List<string>> dict = new  Dictionary<string,List<List<string>>();

有没有简单，优雅的方法来做到这一点？

修改

基本上这就是映射：

"12323" -> ["dfgdfg","ZCxzcx"]
"432234" -> ["asdfds","xcvbcvb"]
"45345435" -> ["wertert","gfhjfgj"]

Answer 1

根据问题更新更新了答案 好的，所以你想要每个值列表中的第n个项目作为值，如下所示：

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();
dictVals.Add(listVal1);
dictVals.Add(listVal2);

Dictionary<string, List<string>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, 
                             entry => new List<string>(){dictVals[0][entry.index], dictVals[1][entry.index]});

基本上，它遍历newDictKeys中的所有键，创建一个临时匿名对象，其中键和该键的索引进入newDictKeys列表（所以{"12323", 0}, {"432234", 1}, ...）。然后，它创建一个Dictionary，其中键是来自newDictKeys的值，对于该值，它从同一索引位置的dictValues中的每个子列表中获取值。

或者，简化版（直接访问listVal1和listVal2集合，而不是dictVals：

Dictionary<string, List<string>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, 
                             entry => new List<string>(){listVal1[entry.index], listVal2[entry.index]});

原始答案 如果您想为newDictKeys中的每个条目设置相同的值集，则可以将其映射为：

List<string> newDictKeys = new List<string>(new []{"12323","432234","45345435"});
List<string> listVal1 = new List<string>(new []{"dfgdfg","asdfds","wertert"});
List<string> listVal2 = new List<string>(new []{"ZCxzcx","xcvbcvb","gfhjfgj"});

List<List<string>> dictVals = new List<List<string>>();
dictVals.Add(listVal1);
dictVals.Add(listVal2);

Dictionary<string, List<List<string>>> dict = 
    newDictKeys.ToDictionary(key => key, key => dictVals);

如果您想为newDictKeys中的每个条目设置不同的值集，请将值放入数组中，以便它们与键的顺序相同，您可以使用.Select()获取键列表中键的索引，然后.ToDictionary()映射到您想要的值，如下所示：

var valuesArray = new []{dictVals, dictVals2, ...};

Dictionary<string, List<List<string>>> dict = 
    newDictKeys.Select((key, index) => new {key, index})
               .ToDictionary(entry => entry.key, entry => valuesArray[entry.index]);

valuesArray也可以是一个列表，只要它的值可以由索引器检索。

Answer 2

由于您将为同一个密钥存储两个列表，为什么不将两个列表组合在一起？

   List<string> newDictKeys  = new List<string>{ "12323", "432234", "45345435"};

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string>{ "ZCxzcx", "xcvbcvb", "gfhjfgj" };
    t.AddRange(t2);

    Dictionary<string,List<string>> dict = newDictKeys.ToDictionary(key => key, key => t);

<强>更新

使用对象列表：

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string> { "ZCxzcx", "xcvbcvb", "gfhjfgj" };


    Dictionary<string, List<object>> dict = newDictKeys.ToDictionary(key => key, key => new List<object> {t, t2});

更新2 这应该成为一个技巧：

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    List<string> t = new List<string> { "dfgdfg", "asdfds", "wertert" };
    List<string> t2 = new List<string> { "ZCxzcx", "xcvbcvb", "gfhjfgj" };


    Dictionary<string, List<string>> dict = new Dictionary<string, List<string>>();

    foreach (var key in newDictKeys.Where(key => t.Count > 0 && t2.Count > 0))
    {
        dict.Add(key, new List<string> {t.FirstOrDefault(), t2.FirstOrDefault()});
        t.RemoveAt(0);
        t2.RemoveAt(0);
    }

更新3 使用队列

    List<string> newDictKeys = new List<string> { "12323", "432234", "45345435" };

    Queue<string> t = new Queue<string> (new []{ "dfgdfg", "asdfds", "wertert" });
    Queue<string> t2 = new Queue<string>(new[] { "ZCxzcx", "xcvbcvb", "gfhjfgj" });


    Dictionary<string, List<string>> dict = newDictKeys
    .Where(key => t.Count > 0 && t2.Count > 0)
    .ToDictionary(key => key, key => new List<string> {t.Dequeue(), t2.Dequeue()});

如何使用列表<string>作为字典中的键

修改

2 个答案: