Question

我正在处理一个数据库，其中日期和时间分为两个单独的列，我的任务是显示两个日期和时间间隔之间的记录。

我做了以下查询，但这只给出了两个日期从10到12的记录。我在第二天12到10之间错过了记录。

我该如何做到这一点？

SELECT 
 [guid], 
 [date], 
 [time], 
 [pos]
FROM
  SomeTable
WHERE 
  [guid] = '0Q8m48D_uHua6P0' 
  AND [date] >= '2017-09-12' 
  AND time >= '10:00' 
  AND [date] <= '2017-09-13' 
  AND time <= '12:00';

Answer 1

您当然可以合并它们，然后使用BETWEEN进行过滤，如下所示：

SELECT 
 [guid], 
 [date], 
 [time], 
 [pos]
FROM
  SomeTable
WHERE [guid] = '0Q8m48D_uHua6P0' 
  AND (DATEADD(day, DATEDIFF(day,'19000101', [date]), CAST([time] AS DATETIME2(7)))) BETWEEN '2017-09-12 12:00:00.000' and '2017-09-12 12:00:00.000'

..但这是一个坏主意，因为你的条件有一个函数，将可能使查询优化器忽略你可能有的任何索引（因为这样的查询不是sargable）

所以，我会在你的桌面上创建一个名为[Datetime]的新的持久计算列或任何对你有意义的列，然后给它一个默认值：

DATEADD(day, DATEDIFF(day,'19000101', [date]), CAST([time] AS DATETIME2(7))))

然后您可以按如下方式编写查询：

SELECT 
 [guid], 
 [date], 
 [time], 
 [pos]
FROM
  SomeTable
WHERE [guid] = '0Q8m48D_uHua6P0' 
  AND [Datetime] BETWEEN '2017-09-12 12:00:00.000' and '2017-09-12 12:00:00.000'

Answer 2

有一个开始和结束日期例外的条款：

SELECT [guid], [date], [time], [pos]
FROM [table]
WHERE [guid] = '0Q8m48D_uHua6P0' 
and [date] >= '2017-09-12' AND [time] >= iif([date] = '2017-09-12', '10:00', [time])
AND [date] <= '2017-09-13' AND [time] <= iif([date] = '2017-09-13', '12:00', [time]);

Answer 3

您可以将列计算为DATETIME，然后对其进行过滤。

;with cte as (
    SELECT 
     [guid], 
     [date], 
     [time], 
     [pos],
     DT = cast([date] as datetime) + cast([time] as datetime)
    FROM
      SomeTable
    WHERE 
      [guid] = '0Q8m48D_uHua6P0'
)

select * 
from cte
where DT between '20170912 10:00' and '20170913 12:00'

Answer 4

以下是执行此操作的一种方法

SELECT 
[guid], 
[date], 
[time], 
[pos]
FROM
 SomeTable
WHERE 
 [guid] = '0Q8m48D_uHua6P0' 
AND
CAST   (
CONVERT(Varchar(10), [date], 112) + ' ' +   
CONVERT(Varchar(8), [time]) AS DateTime) Between '2017-09-12 10:00' 
AND '2017-09-13 12:00'

当日期和时间分为两个单独的列时，选择日期和时间范围

4 个答案: