我的存储过程是
ALTER PROCEDURE [dbo].[Register]
@Id int,
@Name nvarchar(50)
AS
BEGIN
BEGIN TRY
INSERT INTO dbo.Group (Id, Name)
VALUES(@Id, @Name)
SELECT 0
END TRY
BEGIN CATCH
SELECT -1
END CATCH
END
GO
我希望将此数据传递给此表
@Id = 1
@Name = 'test1,test2,test3,test4,test5'
并且结果如此
Id Name
1 test1
1 test2
1 test3
1 test4
1 test5
请分享实现这一目标的最佳方式。
答案 0 :(得分:2)
SQL Server 2016提供了string_split()
,它完全符合您的要求:
ALTER PROCEDURE [dbo].[Register] (
@Id int,
@Name nvarchar(max)
) AS
BEGIN
BEGIN TRY
WITH s AS (
SELECT STRING
INSERT INTO dbo.Group (Id, Name)
VALUES(@Id, @Name)
SELECT i.id, s.val
FROM (SELECT @id as id) s CROSS APPLY
STRING_SPLIT(name, ',') s(val)
SELECT 0
END TRY
BEGIN CATCH
SELECT -1
END CATCH
END;
GO
对于早期版本的SQL Server,您可以在网上找到string_split()
的代码。
答案 1 :(得分:2)
您可以使用TVP:
创建用户定义的表类型
CREATE TYPE [dbo].[TestTableType] AS TABLE(
Id [int] NOT NULL,
Name varchar(10)
)
将其作为参数传递给存储过程
ALTER PROCEDURE [dbo].[Register]
@testTable TestTableType READONLY
AS
BEGIN
BEGIN TRY
INSERT INTO dbo.Group (Id, Name)
SELECT *
FROM @testTable
SELECT 0
END TRY
BEGIN CATCH
SELECT -1
END CATCH
END
您可以在documentation中找到更多信息,请注意,当用作存储过程参数时,TVP必须声明为READONLY
。
答案 2 :(得分:0)
首先创建一个split函数,如下所示:
create FUNCTION [dbo].[fnSplit](
@sInputList VARCHAR(max) -- List of delimited items
, @sDelimiter VARCHAR(5) -- delimiter that separates items
) RETURNS @List TABLE (item VARCHAR(max))
BEGIN
DECLARE @sItem VARCHAR(max)
WHILE CHARINDEX(@sDelimiter,@sInputList,0) <> 0
BEGIN
SELECT
@sItem=RTRIM(LTRIM(SUBSTRING(@sInputList,1,CHARINDEX(@sDelimiter,@sInputList,0)-1))),
@sInputList=RTRIM(LTRIM(SUBSTRING(@sInputList,CHARINDEX(@sDelimiter,@sInputList,0)+LEN(@sDelimiter),LEN(@sInputList))))
IF LEN(@sItem) > 0
INSERT INTO @List SELECT @sItem
END
IF LEN(@sInputList) > 0
INSERT INTO @List SELECT @sInputList -- Put the last item in
RETURN
END
然后,您将能够按照这些方式做点什么:
declare @test table
(
id int,
name varchar(20)
)
declare @list varchar(MAX) = 'test1,test2,test3,test4,test5'
declare @id int = 1
INSERT INTO @test SELECT @id, * from dbo.fnSplit(@list,',')
SELECT * FROM @test
返回
1 test1
1 test2
1 test3
1 test4
1 test5
显然你不需要选择,但我只想证明插入工作正常!