我设法发布了几个主题并阅读了其中一个主题。我需要做的是倾听和阅读所有已发布的主题并获取消息。这是我使用的代码:
将消息发布到3个主题:
#!/usr/bin/env python3
import paho.mqtt.client as mqtt
client = mqtt.Client()
client.connect("localhost",1883,60)
client.publish("topic/1", "400 | 350 | 320 | 410");
client.publish("topic/2", "200 | 350 | 420 | 110");
client.publish("topic/3", "200 | 350 | 420 | 110");
client.disconnect();
订阅并阅读1个主题的消息
#!/usr/bin/env python3
import paho.mqtt.client as mqttClient
import time
def on_connect(client, userdata, flags, rc):
if rc == 0:
print("Connected to broker")
global Connected #Use global variable
Connected = True #Signal connection
else:
print("Connection failed")
def on_message(client, userdata, message):
print "Message received : " + message.payload
Connected = False
broker_address= "localhost"
port = 1883
client = mqttClient.Client("Python")
client.on_connect= on_connect
client.on_message= on_message
client.connect(broker_address, port=port)
client.loop_start()
while Connected != True:
time.sleep(0.1)
client.subscribe("topic/2")
try:
while True:
time.sleep(1)
except KeyboardInterrupt:
print "exiting"
client.disconnect()
client.loop_stop()
答案 0 :(得分:0)
您可以多次调用client.subscribe()
函数订阅多个主题。
此外,您应该移动调用以订阅on_connect
回调,以消除对第一个循环的需要。
#!/usr/bin/env python3
import paho.mqtt.client as mqttClient
import time
def on_connect(client, userdata, flags, rc):
if rc == 0:
print("Connected to broker")
client.subscribe("topic/1")
client.subscribe("topic/2")
client.subscribe("topic/3")
client.subscribe("topic/4")
else:
print("Connection failed")
def on_message(client, userdata, message):
print("Message received : " + str(message.payload) + " on " + message.topic)
broker_address= "localhost"
port = 1883
client = mqttClient.Client("Python")
client.on_connect= on_connect
client.on_message= on_message
client.connect(broker_address, port=port)
client.loop_start()
try:
while True:
time.sleep(1)
except KeyboardInterrupt:
print("exiting")
client.disconnect()
client.loop_stop()
编辑:
您还可以使用以下语法一次订阅多个主题
client.subscribe([("topic/1", 0), ("topic/2", 0), ("topic/3", 0),("topic/4", 0)])