Answer 1

经过一番挖掘，我们能够获取传递给管理视图的参数（在被django admin的urls.py解析之后）并使用它（self_pub_id）来获取对象：

class PublicationAdmin(admin.ModelAdmin):

    def formfield_for_manytomany(self, db_field, request, **kwargs):
        if db_field.name == "authors":
            #this line below got the proper primary key for our object of interest
            self_pub_id = request.resolver_match.args[0]

            #then we did some stuff you don't care about
            pub = Publication.objects.get(id=self_pub_id)
            kwargs["queryset"] = pub.authors.all()
        return super(PublicationAdmin, self).formfield_for_manytomany(db_field, request, **kwargs)

更优雅的解决方案是使用已接受的答案推荐并利用get_form ModelAdmin成员函数。像这样：

class ProfileAdmin(admin.ModelAdmin):
    my_id_for_formfield = None
    def get_form(self, request, obj=None, **kwargs):
        if obj:
            self.my_id_for_formfield = obj.id
        return super(ProfileAdmin, self).get_form(request, obj, **kwargs)

    def formfield_for_foreignkey(self, db_field, request, **kwargs):
        if db_field.name == "person":
            kwargs["queryset"] = Person.objects.filter(profile=self.my_id_for_formfield)
        return super(ProfileAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

Answer 2

Answer 3

我通过重写change_view()

使其成功

class CartAdmin(admin.ModelAdmin):

def change_view(self, request, object_id, form_url='', extra_context=None):
    self.object_id = object_id
    return self.changeform_view(request, object_id, form_url, extra_context)


def formfield_for_foreignkey(self, db_field, request, **kwargs):
    print self.object_id
    return super(CartAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs)

然后您可以在self.object_id

内拨打formfield_for_foreignkey()

Answer 4

以下代码段将为您提供对象ID：

request.resolver_match.kwargs['object_id']

示例用法：（我正在过滤显示的电话号码，只显示客户的电话号码

def formfield_for_foreignkey(self, db_field, request, **kwargs):
    if db_field.name == 'preferred_contact_number':
        kwargs['queryset'] = CustomerPhone.objects.filter(customer__pk=request.resolver_match.kwargs['object_id'])
    return super().formfield_for_foreignkey(db_field, request, **kwargs)

P.S：通过调试并遍历可访问变量来找到它。

Answer 5

一种更通用的方法可能是编写一个辅助方法来获取模型实例（如果有），就像您通常使用（有界的）ModelForm一样，然后从中检索id或任何其他属性：

from django.contrib import admin

class MyModelAdmin(admin.ModelAdmin):

    def get_instance(self, request):
        try:
            object_id = request.resolver_match.kwargs['object_id']
            obj = self.get_object(request, object_id)
        except:
            obj = None
        return obj

Answer 6

我通过在model.py中创建一个返回ID

的property（）来实现它

models.py：

class MyModel(models.Model):
    myfield = models.CharField(max_length=75)
    ...
    def get_id(self):
        return str(self.id)
    getid = property(get_id)

admin.py：

from myapp.models import MyModel

class MyModelAdmin(admin.ModelAdmin):
    list_display = ['mylink',]
    def mylink(self, object):
        return '<a href="http://mywebsite/'+object.getid+'/">Edit</a>'
    mylink.allow_tags = True

admin.site.register(MyModel, MyModelAdmin)

Answer 7

我正在处理类似的情况，并且意识到我需要的ID，我可以从模型中获取它自己，因为它是该模型的外键。所以它会是这样的：

cpu = CompanyUser.objects.filter(company__id=self.company_id)

或模型的结构决定了什么。