让我说我有以下DataFrames:
DATAFRAME 1
CFOP Vendas
0 5101 Venda
1 6101 Venda
2 6107 Venda
3 6118 Venda
4 6109 Venda
DATAFRAME 2
Name CFOP Vendas
0 John 5101 10,00
1 Lea 7008 20,00
2 Anthony 6107 15,00
3 Frank 7000 17,00
4 TOM 6109 21,00
我想仅在Dataframe 1的第1行从Dataframe 2算出第2行时才制作第三个Dataframe。
所以,最终的答案应该是:
Name CFOP Vendas
0 John 5101 10,00
2 Anthony 6107 15,00
4 TOM 6109 21,00
我被困了,我只能得到这个代码,我知道这是错的:
vendas_somente = []
for row in df_entrada:
if df_entrada['cfo'] in df_venda['CFOP']:
vendas_somente.append(row)
vendas_somente(10)
韩国社交协会
答案 0 :(得分:1)
或者您可以使用 <!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<style>
#text {
text-align: left;
word-wrap: break-word;
width: 100%;
max-width: 470px;
}
@media all and (max-width: 1300px) {
#text {
text-align: center;
}
}
</style>
</head>
<body>
<div id="text">
just some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random text
just some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random text
just some random textjust some random textjust some random textjust some random textjust some random textjust some random text
just some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random text
just some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random textjust some random text
just some random textjust some random textjust some random textjust some random textjust some random textjust some random text
</div>
</body>
isin
答案 1 :(得分:0)
您可以使用内部合并
创建它In[38]: d1[['CFOP']].merge(d2,how='inner',on='CFOP')
Out[38]:
CFOP Name Vendas
0 5101 John 10,00
1 6107 Anthony 15,00
2 6109 TOM 21,00