在我的主要活动中,我有这一行用viewgroup
MainActivity:
public class ActivityMain extends AppCompatActivity {
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
getSupportFragmentManager().beginTransaction()
.replace(R.id.activity_main_container, new HomeFragment())
.setTransition(FragmentTransaction.TRANSIT_FRAGMENT_OPEN)
.addToBackStack(null)
.commit();
}
}
活动布局:
<android.support.design.widget.CoordinatorLayout
android:layout_width="match_parent"
android:layout_height="match_parent">
<FrameLayout
android:id="@+id/activity_main_container"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:clickable="true"
app:layout_behavior="@string/appbar_scrolling_view_behavior"/>
</android.support.design.widget.CoordinatorLayout>
我的HomeFragment
是:
public class HomeFragment extends Fragment {
public HomeFragment() {
}
@Override
public void onCreate(Bundle saved) {
super.onCreate(saved);
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
View view = inflater.inflate(R.layout.fragment_test, container, false);
Log.e("HomeFragment", " onCreateView");
return view;
}
}
现在在构建应用程序并在模拟器上运行后,我的代码运行重复HomeFragment
,我该如何阻止此操作?
答案 0 :(得分:1)
框架将在活动恢复时恢复您的片段状态,例如在配置更改后。您应该只在第一次创建活动时操作片段。
@Override
protected void onCreate(@Nullable Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if(savedInstanceState == null) {
// set up your fragments
}
}
答案 1 :(得分:0)
如果片段已经启动,请执行此操作 再次
private Class mFragmentClass; mFragmentClass = InfoFragment.class;
if (null != mFragmentClass) {
try {
mFragment = (Fragment) mFragmentClass.newInstance();
if(mFragment instanceof (Fragment)mFragmentClass){
FragmentManager fragmentManager = getSupportFragmentManager(); fragmentManager.beginTransaction().replace(R.id.content_navigation_menu, mFragment).commit();
} catch (InstantiationException exception) { exception.printStackTrace();
} catch (IllegalAccessException exception) { exception.printStackTrace(); }
}else {
//do nothing
}