Question

#include <iostream>

using std::cout;
using std::cin;
using std::string;

int main(){
    cout << "Welcome to the program!";
    cout << "\nWhat is your name? ";
    string name;
    cin >> name;
    cout << "Hi, " << name << ". ";
    cout << "Your name has " << name.length() << " letters!";
    cout << "\nWhat is your last name? ";
    string lastname;
    string *plastname;
    cin >> lastname;
    plastname = &lastname;
    cout << "Your full name is " << name.append(*plastname) << ".";
    cout << " Your full name has " << name.length() + lastname.length() << " letters!";
    return 0;
}

这就是结果：

欢迎来到该计划！
你叫什么名字？ ADK
嗨，adk。你的名字有3个字母！
你的姓氏是什么？ adkl
您的全名是adkadkl。您的全名有11个字母！

3 + 4 = 11怎么样？！

Answer 1

首先，name.append(*plastname)真正将lastname添加到name，使name成为长度为7的字符串（使用您的示例输入）。

然后你打印name.length() + lastname.length()等于7 + 4（记住你之前的追加！），导致11的结果。

或许附加name和lastname，您应该单独打印它们吗？像

cout << "Your full name is " << name << ' ' << lastname << ".\n";

Answer 2

您已将lastname附加到name，然后添加它们，这会给您带来比预期更大的价值

cout << "Your full name is " << name.append(*plastname) << ".";//You append here
cout << " Your full name has " << name.length() + lastname.length() << " letters!";//And then add here

Answer 3

你只需打印name.length（）的name.length（）+ lastname.lenght（），因为你已将姓氏附加到名称。

添加两个单词的长度会产生错误的答案（string0.length（）+ string1.length（））

3 个答案: