Question

@foreach ($getDocs as $key => $docs)
    @foreach ($docs->doc_user as $key1 => $users)
        @foreach ($users->details as $key2 => $value2)

            //Accessing different things here

        @endforeach
    @endforeach
@endforeach

我在form之外有foreachs，我需要$user的ID $user->id，我在上面尝试了隐藏字段 foreachs，并访问该隐藏字段的值，并将该值提供给表单中的隐藏字段。

上述方法存在的问题是$user->id对于每条记录都是相同的。

我该如何解决这个问题。

Answer 1

您可以尝试这样的@foreach ($getDocs as $key => $docs) @foreach ($docs->doc_user as $key1 => $users) @php $user_ids = $users->pluck("id") @endphp @foreach ($users->details as $key2 => $value2) //Accessing different things here @endforeach @endforeach @endforeach

$user_ids

然后使用{{1}}数组

Laravel从foreach获得嵌套的foreach值

1 个答案: