WebElement body = browser.findElement(By.xpath("//body"));
body.findElement(By.xpath("")); // I want to get all child elements
// inside body, but nothing deeper.
示例文档。
<html>
<body>
<div>
</div>
<span>
<table>
</table>
</span>
</body>
</html>
预期结果为div和span。我无法控制文件，而且差异很大。
答案 0 :(得分：30)
("*")给出上下文节点的所有子元素。所以使用：
body.findElement(By.xpath("*"));
答案 1 :(得分：6)
/html/body/*
将仅选择body的直接子元素。
请记住，如果复制所有这些选定节点，则还要复制其内容。因此，如果您执行copy-of，则还会在生成的文档中生成table。
另外，我建议至少阅读XPath基础知识，你会问太多类似的问题。
答案 2 :(得分：4)
这是获取元素的直接子元素的另一种方法：
element.findElement(By.xpath("./*"));
答案 3 :(得分：1)
child代替public class Images {
private String[]eyes=new String[]{
"images/character/face/eyes/blue.png"
};
public LinkedList<Bitmap> eyesBM=new LinkedList<Bitmap>();
private int eyesIndex = 0;
private String[]faceandhands=new String[]{
"images/character/face/faceandhands/white.png",
"images/character/face/faceandhands/black.png"
};
public LinkedList<Bitmap> faceandhandsBM=new LinkedList<Bitmap>();
private int faceandhandsIndex = 0;
private String[]facialhair=new String[]{
"images/character/face/facialhair/black.png"
};
public LinkedList<Bitmap> facialhairBM=new LinkedList<Bitmap>();
private String[]hair=new String[]{
"images/character/face/hair/grey.png"
};
public LinkedList<Bitmap> hairBM=new LinkedList<Bitmap>();
private String[]tattoes=new String[]{
"images/character/face/tattoes/test.png"
};
public LinkedList<Bitmap> tattoesBM=new LinkedList<Bitmap>();
private String[]legs=new String[]{
"images/character/legs/brown.png"
};
private LinkedList<Bitmap> legsBM=new LinkedList<Bitmap>();
private String[]shirt=new String[]{
"images/character/shirt/purple.png"
};
public LinkedList<Bitmap> shirtBM=new LinkedList<Bitmap>();
private String[]shoes=new String[]{
"images/character/shoes/red.png"
};
public LinkedList<Bitmap> shoesBM=new LinkedList<Bitmap>();
private String[]background=new String[]{
"images/character/background/normal.png"
};
public LinkedList<Bitmap> backgroundBM=new LinkedList<Bitmap>();
public Images(Context c) {
loadBitmaps(c,eyes,"eyes");
loadBitmaps(c,faceandhands,"faceandhands");
loadBitmaps(c,facialhair,"facialhair");
loadBitmaps(c,hair,"hair");
loadBitmaps(c,tattoes,"tattoes");
loadBitmaps(c,legs,"legs");
loadBitmaps(c,shirt,"shirt");
loadBitmaps(c,shoes,"shoes");
loadBitmaps(c,background,"background");
}
public Bitmap getBitmapFromAsset(Context context, String filePath) {
AssetManager assetManager = context.getAssets();
InputStream istr;
Bitmap bitmap = null;
try {
istr = assetManager.open(filePath);
bitmap = BitmapFactory.decodeStream(istr);
} catch (IOException e) {
System.out.println("Fudeu geral !");
}
return bitmap;
}
public void loadBitmaps(Context c,String[] src,String dest){
Bitmap bit=null;
for (int i = 0;i<src.length;i++){
bit= getBitmapFromAsset(c,src[i]);
switch (dest){
case "eyes":
eyesBM.add(bit);
break;
case "faceandhands":
faceandhandsBM.add(bit);
break;
case "facialhair":
facialhairBM.add(bit);
break;
case "hair":
hairBM.add(bit);
break;
case "tattoes":
tattoesBM.add(bit);
break;
case "legs":
legsBM.add(bit);
break;
case "shirt":
shirtBM.add(bit);
break;
case "shoes":
shoesBM.add(bit);
break;
case "background":
backgroundBM.add(bit);
break;
}
//dest.add(bit);
//dest.add(BitmapFactory.decodeResource(r, src[i]));
}
}
public Bitmap getBitmap(String name){
switch (name){
case "eyes":
eyesIndex=eyesIndex>=eyesBM.size()?0:eyesIndex;
Bitmap aux =eyesBM.get(eyesIndex);
eyesIndex++;
return aux;
case "faceandhands":
faceandhandsIndex=faceandhandsIndex>=faceandhandsBM.size()?0:faceandhandsIndex;
Bitmap aux1=faceandhandsBM.get(faceandhandsIndex);
faceandhandsIndex++;
return aux1;
//return faceandhandsBM.get(0);
case "facialhair":
return facialhairBM.get(0);
case "hair":
return hairBM.get(0);
case "tattoes":
return tattoesBM.get(0);
case "legs":
return legsBM.get(0);
case "shirt":
return shirtBM.get(0);
case "shoes":
return shoesBM.get(0);
case "background":
return backgroundBM.get(0);
}
return null;
}}
可以帮助某人。