Oracle ORA-00979 - “不是GROUP BY表达式”

时间:2011-01-05 15:46:30

标签: sql oracle ora-00979

有人可以帮我解决这个问题吗?我在尝试运行时遇到了ORA-00979:

select   t0.title, count (1) as count0, (select   count (1)
      from contract c1, se se1
      where c1.c_id = se1.c_id
      and se1.svc_id = 3
      and se1.deleted = 0
      and c1.deleted = 0
      and c1.c_date between to_date ('07.10.2000', 'dd.mm.yyyy') 
                        and to_date ('22.11.2010', 'dd.mm.yyyy')
      and c1.company = 0
      and c1.tdata.tariff = c0.tdata.tariff
    ) as count1
  from contract c0, se se0, tariff t0
  where c0.c_id = se0.c_id
  and se0.svc_id = 3
  and se0.deleted = 0
  and c0.deleted = 0
  and c0.c_date between to_date ('21.11.2000', 'dd.mm.yyyy') 
                and to_date ('06.01.2011', 'dd.mm.yyyy')
  and c0.company = 0
  and t0.tariff_id = c0.tdata.tariff
  group by t0.title

4 个答案:

答案 0 :(得分:3)

问题是您的子查询select count(1)部分。仅仅因为它有一个计数它实际上并没有使它成为一个聚合。它仍然是一个子查询,将应用于每一行,您可以看到它使用的值c0.tdata.tariff不属于该组。

答案 1 :(得分:1)

看起来标量子查询导致了问题 - 它既不是组函数,也不在GROUP BY列表中。

可能你可以通过以下方式解决问题:

select   t0.title, count (1) as count0, SUM(select   count (1) ...) AS count1
 ...

答案 2 :(得分:1)

考虑到这似乎只是在不同日期的同一查询的两个实例(我可能在这里错了...这是漫长的一天),你可能只是简化它并重写如下:

select
  t0.title, 
  count (case when c0.c_date between to_date ('21.11.2000', 'dd.mm.yyyy') 
                and to_date ('06.01.2011', 'dd.mm.yyyy') then 1 end) as count0,
  count (case when c0.c_date between to_date ('07.10.2000', 'dd.mm.yyyy') 
                and to_date ('22.11.2011', 'dd.mm.yyyy') then 1 end) as count1
from 
  contract c0, 
  se se0, 
  tariff t0
where 
  c0.c_id = se0.c_id
  and se0.svc_id = 3
  and se0.deleted = 0
  and c0.deleted = 0
  and (c0.c_date between to_date ('21.11.2000', 'dd.mm.yyyy') 
                and to_date ('06.01.2011', 'dd.mm.yyyy')
    or c0.c_date between to_date ('07.10.2000', 'dd.mm.yyyy') 
                        and to_date ('22.11.2010', 'dd.mm.yyyy'))
  and c0.company = 0
  and t0.tariff_id = c0.tdata.tariff
group by t0.title

答案 3 :(得分:0)

您的群组需要包含选择列表中的所有非汇总列。在这种情况下,group by缺少子查询返回的count1