使用matplotlib或seaborn绘制两列之间的关系

Question

我的数据框中有两列。日期格式的其中一列。另一列有1＆0;和0＆＃39; s。我想绘制一个显示两列之间关系的图表。这是我的数据的一小部分

-(UIImage*)merge:(UIImage*)img1 img2:(UIImage*)img2{
    CGFloat h = img1.size.height;
    CGFloat w = img1.size.width + img2.size.width;

    CGSize size = CGSizeMake(w, h);
    UIGraphicsBeginImageContextWithOptions(size, NO, 1.0);
    [img1 drawInRect:CGRectMake(0,0,img1.size.width, img1.size.height)];
    [img2 drawInRect:CGRectMake(0,0,img2.size.width, img2.size.height)];

    UIImage *finalImage = UIGraphicsGetImageFromCurrentImageContext();
    UIGraphicsEndImageContext();

    return finalImage;
}

情节应该是1日和1日相对于日期特别是月份部分的分布，以便我可以决定哪个月有更多的1和更多0＆ ＃39; S。提前致谢

Answer 1

我使用条形图

df['Consumer disputed?'].groupby(df['Date received'].dt.month).sum().plot.bar()

Answer 2

您可以使用Seaborn的联合图

data['month'] = pd.to_datetime(data['Date']).dt.month
sns.jointplot(x='Consumer',y='month',data=data)]

Answer 3

有些事情......

import matplotlib.pyplot as plt
% matplotlib inline
df['Date'] = pd.to_datetime(df['Date'])
x = df['Date'].values
y = df['received'].values
plt.scatter(x,y)
plt.show()

Answer 4

这是我的问题的解决方案。

#extract the month form the date

train_data['month'] = pd.to_datetime(train_data['Date received']).dt.month

#crosstab displays the frequency distribution of the variable
#(here "Consumer  disputed?") in a matrix format` 
b = pd.crosstab(train_data['month'], train_data['Consumer disputed?'])


#transform the label month into a column
b.reset_index(level='month', inplace=True)

#plot the graph
b.plot('month', 'Yes')