Question

我试图用Java编写一个（暴力）解决方案来解决这个问题：

import java.lang.*;

public class TwoSum {
    public int[] twoSum(int[] nums, int target) {
        for (int i = 0; i < nums.length; i++) {
            for (int j = i+1; j < nums.length; j++) {
                if (nums[j] == target - nums[i]) {
                    return new int[] {i, j};
                }
            }
        }
    }
    throw new IllegalArgumentException("No two sum solution");
}

但是，当我尝试编译它时，我收到以下错误：

/home/kurt/Documents/Algorithms/TwoSum.java:13: error: illegal start of type
    throw new IllegalArgumentException("No two sum solution");
    ^
/home/kurt/Documents/Algorithms/TwoSum.java:13: error: ';' expected
    throw new IllegalArgumentException("No two sum solution");
         ^
/home/kurt/Documents/Algorithms/TwoSum.java:13: error: invalid method declaration; return type required
    throw new IllegalArgumentException("No two sum solution");
              ^
/home/kurt/Documents/Algorithms/TwoSum.java:13: error: illegal start of type
    throw new IllegalArgumentException("No two sum solution");
                                       ^
4 errors
[Finished in 0.8s with exit code 1]

我有点难过可能导致错误的原因？（我从示例代码段中获取了代码，但没有注意到任何差异）。

Answer 1

使用以下代码：

evaluate=False

在这种情况下，import java.lang.*; public class TwoSum { public int[] twoSum(int[] nums, int target) { for (int i = 0; i < nums.length; i++) { for (int j = i+1; j < nums.length; j++) { if (nums[j] == target - nums[i]) { return new int[] {i, j}; } } } throw new IllegalArgumentException("No two sum solution"); } }是内部方法。

Java＆＃34;错误：非法启动类型＆＃34;抛出IllegalArgumentException时

1 个答案: