这是我的代码
<table cellspacing="0" cellpadding="0"><tbody>
<tr>
<xsl:for-each select="/*/nearme/location">
<td>
<input type="radio" name="rf" id="rf" class="page_checkbox"/><label for="rf1"><span></span><xsl:value-of select="."/></label>
</td>
<xsl:if test="position() mod 5=0">
</tr><tr>
</xsl:if>
</xsl:for-each>
</tr>
</tbody></table>
如果您看到有一个xsl if test
确定该位置是否为模数5.如果是,我想结束tr
并开始一个新的tr
但是它会打破这个当前的代码。
知道如何解决这个问题吗?
更新:
这是我的xml:
<nearme>
<location id="538">Pleasures</location>
<location id="541">Baby Dolls</location>
<location id="1521">Michelle's Beach House</location>
<location id="1886">Wild Wild West Gentlemen's Club</location>
<location id="993">Sadies</location>
<location id="5381">ABC</location>
<location id="541">DEF</location>
<location id="1521">ghi</location>
<location id="1886">FDFFDSFD</location>
<location id="993">HGHHFH</location>
</nearme>
这是我的预期输出:
<table cellspacing="0" cellpadding="0"><tbody>
<tr>
<td>
<input type="radio" name="rf" id="rf1" class="page_checkbox"/><label for="rf1"><span></span>Pleasures</label>
</td>
<td>
<input type="radio" name="rf" id="rf2" class="page_checkbox"/><label for="rf2"><span></span>Baby Dolls</label>
</td>
<td>
<input type="radio" name="rf" id="rf3" class="page_checkbox"/><label for="rf3"><span></span>Michelle's Beach House</label>
</td>
<td>
<input type="radio" name="rf" id="rf4" class="page_checkbox"/><label for="rf4"><span></span>Wild Wild West Gentlemen's Club</label>
</td>
<td>
<input type="radio" name="rf" id="rf5" class="page_checkbox"/><label for="rf5"><span></span>Sadies</label>
</td>
</tr>
<tr>
<td>
<input type="radio" name="rf" id="rf6" class="page_checkbox"/><label for="rf6"><span></span>ABC</label>
</td>
<td>
<input type="radio" name="rf" id="rf7" class="page_checkbox"/><label for="rf7"><span></span>DEF</label>
</td>
<td>
<input type="radio" name="rf" id="rf8" class="page_checkbox"/><label for="rf8"><span></span>ghi</label>
</td>
<td>
<input type="radio" name="rf" id="rf9" class="page_checkbox"/><label for="rf9"><span></span>FDFFDSFD</label>
</td>
<td>
<input type="radio" name="rf" id="rf10" class="page_checkbox"/><label for="rf10"><span></span>HGHHFH</label>
</td>
</tr>
</tbody></table>
答案 0 :(得分:1)
To simplify the example to the minimum necessary to demonstrate the problem, consider the following:
XML
PictureBox
XSLT 1.0
Bitmap screenshot = TakeScreenshot();
pictureBox1.Image = screenshot;
Result
___
答案 1 :(得分:0)
You have to use grouping.
In XSLT 2.0 you can use #headerimg {
background: url(http://www.adamoxenhamsmith.co.uk/site/img/NewYork.jpg) no-repeat center center fixed;
-webkit-background-size: cover;
-moz-background-size: cover;
-o-background-size: cover;
background-size: cover;
, grouping by 5 adjacent
#include <bits/stdc++.h>
using namespace std;
#define ii pair<int,int>
bool modified_sort(const pair<int,int> &a,
const pair<int,int> &b)
{
if (a.first == b.first) {
return (a.second <b.second);
}
return (a.first <b.first);
}
int main() {
// your code goes here
vector<ii> blocks;
int n; // no of blocks
int a,b;
cin>>n;
for (int i=0;i<n;i++) {
cin>>a>>b;
blocks.push_back(ii(a,b));
}
sort(blocks.begin(), blocks.end(), modified_sort);
int start=0,end=0;
int max_height=0;
while(end<n) {
while(start<end && blocks[start].second <= blocks[end].first)
{
start++;
}
max_height = max(max_height,(end-start+1));
end++;
}
cout<<max_height<<endl;
return 0;
}
elements.
For each of the above groups generate a if (!this.IsHandleCreated)
this.CreateControl();
this.Invoke((MethodInvoker)delegate
{
//do so
});
element.
Inside it you must place a loop iterating through the current
group, generating for-each-group
elements, with location
and tr
inside.
Below you have an example code:
td