Question

我想从C＃程序集中提取构建版本，作为在Windows服务器上运行的Jenkins管道的一部分。程序集文件如下所示：

// [...snip...]

[assembly: AssemblyConfiguration("")]
[assembly: AssemblyCompany("")]
[assembly: AssemblyProduct("BulkUpdater")]
[assembly: AssemblyCopyright("Copyright ©  2016")]

// [...snip...]

// [assembly: AssemblyVersion("1.0.*")]
[assembly: AssemblyVersion("3.4.1.9")]
[assembly: AssemblyFileVersion("3.4.1.9")]

我对Jenkins很新，但熟悉Groovy，所以我转向使用明显的Groovy工具来实现这一目标：

String captureVersionFromAssembly(String assemblyFilename) {
  String version
  File file = new File(assemblyFilename)
  file.eachLine { line ->
    // avoid commented AssemblyVersion
    if (line.contains("AssemblyVersion") && !line.startsWith('//')) {
      version = line.split('"')[1]
    }
  }
  version
}

正确地将3.4.1.9返回到Jenkins管道之外。

我知道Jenkins管道插件要求您授予管道脚本使用File类的权限。我是通过在in-process script approval的{{1}}部分注册来完成此操作的。

在Jenkins管道中，Manage Jenkins类似乎无法找到文件（即使File显示它们在那里。）

bat 'dir'

给出以下日志：

dir('omega-elms')  {
    bat 'dir'
    bat 'dir ELMS_Desktop_Application'
    echo "Working directory: ${pwd()}"
    fileExists('ELMS_Desktop_Application')
    fileExists('ELMS_Desktop_Application\\CARS')
    fileExists('ELMS_Desktop_Application\\CARS\\BulkUpdater')
    fileExists('ELMS_Desktop_Application\\CARS\\BulkUpdater\\Properties')
}

def fileExists(String filename) {
   echo "'$filename' exists? ${new File(filename).exists()}"
}

我还在工作目录前面添加了一个绝对文件路径：

[windows] E:\Jenkins\Production\workspace\test_version_extract_buildonly\omega-elms>dir
[windows]  Volume in drive E is New Volume
[windows]  Volume Serial Number is 6695-F35A
[windows]
[windows]  Directory of E:\Jenkins\Production\workspace\test_version_extract_buildonly\omega-elms
[windows]
[windows] 29/08/2017  11:38 AM    <DIR>          .
[windows] 29/08/2017  11:38 AM    <DIR>          ..
[windows] 29/08/2017  11:38 AM    <DIR>          ELMS_Desktop_Application
[windows]                0 File(s)              0 bytes
[windows]                3 Dir(s)  105,175,678,976 bytes free
[Pipeline] [windows] bat
[windows] [omega-elms] Running batch script
[windows]
[windows] E:\Jenkins\Production\workspace\test_version_extract_buildonly\omega-elms>dir ELMS_Desktop_Application
[windows]  Volume in drive E is New Volume
[windows]  Volume Serial Number is 6695-F35A
[windows]
[windows]  Directory of E:\Jenkins\Production\workspace\test_version_extract_buildonly\omega-elms\ELMS_Desktop_Application
[windows]
[windows] 29/08/2017  11:38 AM    <DIR>          .
[windows] 29/08/2017  11:38 AM    <DIR>          ..
[windows] 29/08/2017  11:38 AM    <DIR>          AppData
[windows] 29/08/2017  11:38 AM    <DIR>          CARS
[windows] 29/08/2017  11:38 AM             1,322 README.md
[windows] 29/08/2017  11:38 AM    <DIR>          Tests
[windows]                1 File(s)          1,322 bytes
[windows]                5 Dir(s)  105,175,674,880 bytes free
[Pipeline] [windows] pwd
[Pipeline] [windows] echo
[windows] Working directory: E:\Jenkins\Production\workspace\test_version_extract_buildonly\omega-elms
[Pipeline] [windows] pwd
[Pipeline] [windows] echo
[windows] 'ELMS_Desktop_Application' exists? false
[Pipeline] [windows] echo
[windows] 'ELMS_Desktop_Application\CARS' exists? false
[Pipeline] [windows] echo
[windows] 'ELMS_Desktop_Application\CARS\BulkUpdater' exists? false
[Pipeline] [windows] echo
[windows] 'ELMS_Desktop_Application\CARS\BulkUpdater\Properties' exists? false
[Pipeline] [windows] echo
[windows] 'ELMS_Desktop_Application\CARS\BulkUpdater\Properties\AssemblyInfo.cs' exists? false

但这并没有解决问题。

有什么建议吗？

Answer 1

以下是丑陋但有效：

appversion.bat中的assemblyDir：

@echo off
REM extract version from assembly ignoring commented out version
FOR /F delims^=^"^ tokens^=1^,2^* %%A IN ('findstr /L /B /C:"[assembly: AssemblyVersion" "AssemblyInfo.cs"') DO (
   set "version=%%B"
)
echo %version%

在Jenkins管道中：

String versionNumber
dir(assemblyDir) {
  bat './appversion.bat >stdout'
  versionNumber = readFile('stdout').trim()
}
// ...use versionNumber here

尚不清楚为什么File方法无法在Jenkins管道中找到文件。理解得更好会很有趣。例如，这是一个故意的安全功能吗？

从C＃程序集中提取版本作为Jenkins管道的一部分

1 个答案: