在运行curl命令以通过java脚本获取请求标头时没有输出

Question

请在我的Java脚本下面找到运行curl命令的命令，该命令必须获取所有请求标头。

public class Test 
{

public static void main(String[] args) throws ClientProtocolException, IOException 
{
    String url="https://www.url.com/";
    String[] command = {"curl", "-v", "--header", "Pragma: x-cache-on,x-cache-remote-on,x-check-cacheable,x-get-cache-key,x-get-extracted-values,x-get-nonces,x-get-ssl-client-session-id,x-get-true-cache-key,x-serial-no,-x-get-request-id", url};
    ProcessBuilder process = new ProcessBuilder(command); 
    Process p;
    try
    {
        p = process.start();
        BufferedReader reader =  new BufferedReader(new InputStreamReader(p.getInputStream()));
        System.out.println("reading: "+reader.readLine()); //Not getting any output
        StringBuilder builder = new StringBuilder();
        String line = null;
        while ( (line = reader.readLine()) != null)
        {
                builder.append(line);
                builder.append(System.getProperty("line.separator"));
        }
        String result = builder.toString();
        System.out.print("output: "+result); //No output
}
    catch (Exception e)
    {
        System.out.print("error"); //No exception
        e.printStackTrace();
    }

}

}

当我在命令提示符下运行上面提到的curl命令时，我能够得到正确的输出。

请帮我在Java脚本中获取相同的输出。