我有两个CGI文件：
script1.sh：
#!/bin/bash
echo "Content-type: text/html"
echo ""
echo "<html>"
echo "<body>"
echo "<form action="/cgi-bin/gene-to-structure/NM_002014-
NP_002005.1/script5.sh" method="GET">"
echo "<p><input type="checkbox" name="residue" value="V---M">
<br></p>"
echo "<p><input type="checkbox" name="residue" value="K---N">
<br></p>"
echo "<input type="submit" value="Submit">"
echo "</form>"
echo "</body>"
echo "</html>"
在上面的单击“提交”按钮的脚本中，我被带到“script5.sh”CGI脚本。我想检索文件的“文件名”（script1.sh），点击“提交”按钮后，我来到“script5.sh”。你能告诉我怎么做吗？
所以，我想在“script5.sh”中执行此操作：
Script5.sh
#!/bin/bash
echo "Content-type: text/html"
echo ""
echo "The file name of the file is "script1.sh"".
非常感谢你！