Question

    #!/usr/bin/python
    import os
    import pathlib
    import os.path
    from datetime import datetime
    i = datetime.now()
    datess = i.strftime('%d')
    months = ["Unknown",
              "Jan",
              "Feb",
              "Mar",
              "Apr",
              "May",
              "Jun",
              "Jul",
              "Aug",
              "Sep",
              "Oct",
              "Nov",
              "Dec"]

    now = (datetime.now())
    year = (now.year)
    print (year)
    month = (months[now.month])
    print(month)
    # I want to print C:\apache-tomcat\store\retail_sector\sugar\Year.month/date
    #The exact path is C:\apache-tomcat\store\retail_sector\sugar\2017.aug/24 but i want to print the year and date as varible 
    p = pathlib.Path('C:\apache-tomcat\store\retail_sector\sugar\2017.aug/24')
    if p.is_dir(): 
    print "Directory is created"

文件路径是C：\ apache-tomcat \ store \ retail_sector \ sugar \ 2017.aug / 24但我希望打印年份日期为可变，如C：\ apache-tomcat \ store \ retail_sector \ sugar \ Year.month /日期。请帮助我如何做到这一点。

Answer 1

如果我理解你想要做什么，一种可能性是使用time.strftime function，它允许您将日期转换为指定的格式：

import time

now = time.localtime()

date_string = time.strftime('%Y.%b/%d', now)
print(date_string)

这将打印

'2017.Aug/24'

'%Y.%b/%d'部分指定格式，%Y表示年份，%b表示缩写的月份名称，%d表示月份的日期。您可以在documentation中找到完整的可用格式列表。

然后，您可以使用date_string构建路径：

path_string = '/my/test/path/%s' % date_string
print(path_string)

这将打印：

'/my/test/path/2017.Aug/24'

如果您希望月份为小写，则可以使用

path_string = '/my/test/path/%s' % date_string.lower()

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