我是Async / Await的新手。我必须将api和sace结果调用到txt文件中。我使用webclient.OpenRead并能够保存文件。我想运行我的代码与API的多个输入,我想并行运行它。
对于顺序操作,我使用WebClient.OpenRead()作为代码工作。
class Program
{
static void Main(string[] args)
{
var name = "test1";
var filename = $"c:\\temp\\{name}.txt";
var url = $"https://testapi?name eq '{name}')";
using (var client = new WebClient())
{
using (Stream stream = client.OpenRead(url))
using (StreamReader streamReader = new StreamReader(stream))
using (JsonTextReader reader = new JsonTextReader(streamReader))
{
reader.SupportMultipleContent = true;
var serializer = new JsonSerializer();
var parsedData = serializer.Deserialize(reader).ToString();
File.WriteAllText(filename, parsedData);
Console.WriteLine($"Result save at {filename}");
}
}
}
}
对于并行操作,我尝试使用WebClient.OpenReadAsync()但我的代码没有将文件保存在c:\ temp \
中static void Main(string[] args)
{
var names = new string[] { "test1", "test2" };
foreach (var name in names)
{
var filename = $"c:\\temp\\{name}.txt";
var url = $"https://testapi?name eq '{name}') ";
var client = new WebClient();
client.OpenReadCompleted += (sender, e) =>
{
Stream reply = (Stream)e.Result;
StreamReader s;
s = new StreamReader(reply);
using (JsonTextReader reader = new JsonTextReader(s))
{
reader.SupportMultipleContent = true;
var serializer = new JsonSerializer();
var parsedData = serializer.Deserialize(reader).ToString();
File.WriteAllText(filename, parsedData);
Console.WriteLine($"Result save at {filename}");
}
};
client.OpenReadAsync(new Uri(url));
}
}
我的代码出了什么问题?有什么指针吗?
答案 0 :(得分:4)
以下是与您的任务并行的代码。请注意,我不使用foreach循环,在您的情况下,这将意味着顺序任务执行。重要的是,首先我创建一个应该执行的任务列表,然后通过包装任务列表创建一个Task.WhenAll的任务,然后我等待任务结束.Wait();
另外,请阅读.Wait()。以及它的行为方式。它有效地阻止了应用程序的线程,这在更复杂的应用程序中是不可取的。
static void Main(string[] args)
{
var tasks = new[] {"test1", "test2"}.Select(SaveData);
Task.WhenAll(tasks).Wait();
}
private static async Task SaveData(string fileName)
{
var filename = $"c:\\temp\\{fileName}.txt";
var url = $"https://testapi?name eq '{fileName}') ";
var client = new WebClient();
client.OpenReadCompleted += (sender, e) =>
{
var reply = e.Result;
StreamReader s;
s = new StreamReader(reply);
using (var reader = new JsonTextReader(s))
{
reader.SupportMultipleContent = true;
var serializer = new JsonSerializer();
var parsedData = serializer.Deserialize(reader).ToString();
File.WriteAllText(filename, parsedData);
Console.WriteLine($"Result save at {fileName}");
}
};
await client.OpenReadTaskAsync(new Uri(url));
}