Question

您好我在C＃中使用Microsoft BotFramework创建了我的第一个测试机器人。在private async Task< Activity > HandleSystemMessage(Activity message)中if (message.Type == ActivityTypes.ConversationUpdate)通常它应该通知添加到组中的新成员或者某人点击Telegram Messenger中bot的开始按钮。当我使用BotFramework模拟器在调试模式下测试时，一切都运行良好但在我发布之后我看到在电报信使中点击开始按钮之后我的代码没有运行。我的代码在ActivationType.ConversationUpdate

foreach (var item in message.MembersAdded)
                {
    try
    {
        using (var dbcontext = new WatermarkBotDBEntities())
        {
            dbcontext.BotUsers.Add(new BotUser()
            {
               AddedFriends = 0,
               ConversationID = message.Conversation.Id,
               ServiceUrl = message.ServiceUrl,
               UserID = message.From.Id
            });
         dbcontext.SaveChanges();
         if (Request.RequestUri.Query != "")
         {
             var u = dbcontext.BotUsers.Where(x => x.BotSalCode == Request.RequestUri.Query.Replace("?start=", string.Empty)).FirstOrDefault();
             u.AddedFriends++;
             dbcontext.Entry(u).State = System.Data.Entity.EntityState.Modified;
             if (u != null)
             {
                 var connector = new ConnectorClient(new Uri(u.ServiceUrl));
                 IMessageActivity newMessage = Activity.CreateMessageActivity();
                 newMessage.Type = ActivityTypes.Message;
                //newMessage.From = new ChannelAccount("<BotId>", "<BotName>");
                newMessage.From = new ChannelAccount("c3e7mhdafcecn7ng3", "Bot");
                newMessage.Conversation = new ConversationAccount(false, u.ConversationID);
                newMessage.Recipient = new ChannelAccount(u.UserID);
                if (u.AddedFriends <= 2)
                    newMessage.Text = $"SomeText.";
                else newMessage.Text = "SomeTex";
                await connector.Conversations.SendToConversationAsync((Activity)newMessage);
                 dbcontext.SaveChanges();
           }
        }
    }
}
catch (Exception ex)
{
}

那么怎么可能在电报中检测到打击开始？此致

Answer 1

我意识到这不是一个完整的答案，但我想与你分享这些代码以防万一。以下是发送欢迎信息的推荐方法，您可以重新使用此代码供您使用。

else if (message.Type == ActivityTypes.ConversationUpdate || message.Type == ActivityTypes.Message)
            {
                IConversationUpdateActivity iConversationUpdated = message as IConversationUpdateActivity;
                if (iConversationUpdated != null)
                {
                    ConnectorClient connector = new ConnectorClient(new System.Uri(message.ServiceUrl));

                    foreach (var member in iConversationUpdated.MembersAdded ?? System.Array.Empty<ChannelAccount>())
                    {
                        // if the bot is added, then
                        if (member.Id == iConversationUpdated.Recipient.Id)
                        {
                            var reply = ((Activity)iConversationUpdated).CreateReply(
                            $"Hi! I'm Botty McBot.");
                            await connector.Conversations.ReplyToActivityAsync(reply);
                        }
                    }
                }
            }

Answer 2

这是我经过大量测试后找到的问题的答案：在public async Task<HttpResponseMessage> Post([FromBody]Activity activity)函数中的MessagesController类中，默认情况下在BotFramework应用程序中定义，您必须执行以下操作：

if (activity.Type == ActivityTypes.Message)
{
    if (activity.Text.StartsWith("/start"))
    {
        //This will return you the start parameter of a link like : http://telegram.me/botname?start=Parameter
        var Parameter = activity.Text.Replace("/start ", "");
    }
}

如果您想发送欢迎信息，那么您肯定可以使用@JasonSowers所说的方式并使用他的代码发送您的信息。最诚挚的问候

ConversationUpdate在发布后不会触发

2 个答案: