我需要获得的是将所有行动态地作为列返回，以防标签值存在多个相同的值（例如Phone，Phone1，Phone2）：
对于isActive=1 and IsPrincipal=1的数据，将显示在没有编号的列上（例如电话，传真，电子邮件）
create table #Contacts
(
ContactID int,
LabelID int,
Label nvarchar(25),
[Value] nvarchar(25),
IsActive bit,
IsPrimary bit,
CustomerID int
)
insert into #Contacts
values
(1, 1, 'Phone', '(541) 754-3010', 1, 1, 1),
(2, 1, 'Phone', '(541) 764-3011', 1, 1, 2),
(3, 1, 'Phone', '(541) 754-3013', 1, 0, 2),
(4, 1, 'Phone', '(541) 754-3014', 1, 0, 2),
(5, 2, 'Phone personal', '1111 111 1111', 1, 1, 2),
(6, 3, 'Fax', '+44 41 444-5555', 1, 1, 2),
(7, 3, 'Fax', '+44 41 444-5595', 1, 0, 2),
(8, 4, 'E-mail', 'John@sales.com', 1, 0, 1),
(9, 4, 'E-mail', 'office@ExpertBike.com', 1, 1, 1),
(10, 4, 'E-mail', 'Mary@purchasing.com', 1, 0, 1)
create table #Customer (CustomerID int, [Name] nvarchar(30))
insert into #Customer
values
(1, 'Sport Playground'),
(2, 'Expert Bike EU')
加入此表后我需要显示的内容如下所示：
Customer Name Phone Phone1 Phone2 Phone personal Fax Fax1 E-mail E-mail1 E-mail2
Sport Playground (541) 754-3010 office@ExpertBike.com John@sales.com Mary@purchasing.com
Expert Bike EU (541) 764-3011 (541) 754-3013 (541) 754-3014 1111 111 1111 +44 41 444-5555 +44 41 444-5595
这个要求让我陷入困境。
答案 0 :(得分：0)
以下内容应该可以解决问题...
SET NOCOUNT ON;
IF OBJECT_ID('tempdb..#Contacts', 'U') IS NOT NULL
DROP TABLE #Contacts;
CREATE TABLE #Contacts (
ContactID int,
LabelID int,
Label nvarchar(25),
[Value] nvarchar(25),
IsActive bit,
IsPrimary bit,
CustomerID int
);
insert into #Contacts
values
(1, 1, 'Phone', '(541) 754-3010', 1, 1, 1),
(2, 1, 'Phone', '(541) 764-3011', 1, 1, 2),
(3, 1, 'Phone', '(541) 754-3013', 1, 0, 2),
(4, 1, 'Phone', '(541) 754-3014', 1, 0, 2),
(5, 2, 'Phone personal', '1111 111 1111', 1, 1, 2),
(6, 3, 'Fax', '+44 41 444-5555', 1, 1, 2),
(7, 3, 'Fax', '+44 41 444-5595', 1, 0, 2),
(8, 4, 'E-mail', 'John@sales.com', 1, 0, 1),
(9, 4, 'E-mail', 'office@ExpertBike.com', 1, 1, 1),
(10, 4, 'E-mail', 'Mary@purchasing.com', 1, 0, 1);
IF OBJECT_ID('tempdb..#Customer', 'U') IS NOT NULL
DROP TABLE #Customer;
CREATE TABLE #Customer (
CustomerID int,
[Name] nvarchar(30)
);
insert into #Customer
values
(1, 'Sport Playground'),
(2, 'Expert Bike EU');
--=======================================================
--=======================================================
IF OBJECT_ID('tempdb..#ContactLabelRN', 'U') IS NOT NULL
DROP TABLE #ContactLabelRN;
SELECT
c.ContactID, c.LabelID, c.Label, c.Value, c.IsActive, c.IsPrimary, c.CustomerID,
rn = ROW_NUMBER() OVER (PARTITION BY c.CustomerID, c.Label ORDER BY c.IsPrimary DESC, c.ContactID ASC) - 1
INTO #ContactLabelRN
FROM
#Contacts c
WHERE
c.IsActive = 1
ORDER BY
c.ContactID;
-------------------------------------------------
DECLARE
@ContactLabel VARCHAR(8000) = '',
@sql VARCHAR(8000) = '',
@DeBug BIT = 0;
WITH
cte_LabelRN AS (
SELECT DISTINCT
clr.LabelID,
clr.Label,
clr.rn
FROM
#ContactLabelRN clr
)
SELECT
@ContactLabel = CONCAT(@ContactLabel, ',
[', lr.Label, NULLIF(lr.rn, 0), '] = MAX(CASE WHEN clr.Label = ''', lr.Label, ''' AND clr.rn = ', lr.rn, ' THEN clr.[Value] END)')
FROM
cte_LabelRN lr
ORDER BY
lr.LabelID,
lr.rn;
SET @sql = CONCAT('
SELECT
[Customer Name] = c.[Name]',
@ContactLabel, '
FROM
#ContactLabelRN clr
JOIN #Customer c
on clr.CustomerID = c.CustomerID
GROUP BY
c.[Name];')
IF @DeBug = 1
BEGIN
PRINT(@sql);
END;
ELSE
BEGIN
EXEC(@sql);
END;
结果...
Customer Name Phone Phone1 Phone2 Phone personal Fax Fax1 E-mail E-mail1 E-mail2
------------------------------ ------------------------- ------------------------- ------------------------- ------------------------- ------------------------- ------------------------- ------------------------- ------------------------- -------------------------
Expert Bike EU (541) 764-3011 (541) 754-3013 (541) 754-3014 1111 111 1111 +44 41 444-5555 +44 41 444-5595 NULL NULL NULL
Sport Playground (541) 754-3010 NULL NULL NULL NULL NULL office@ExpertBike.com John@sales.com Mary@purchasing.com
答案 1 :(得分：0)
您也可以使用PIVOT
WITH t_comp AS
(SELECT t.Name,
CASE WHEN t.IsPrimary = 0
THEN CONCAT(t.Label,CAST(rnum AS VARCHAR))
ELSE t.Label
END Label,
t.Value
FROM (SELECT cn.*,
cs.Name,
ROW_NUMBER() OVER (PARTITION BY cn.CustomerID, cn.LabelID, cn.IsPrimary ORDER BY cn.IsPrimary DESC) rnum
FROM #Contacts cn
INNER JOIN #Customer cs
ON cn.CustomerID = cs.CustomerID
) t
)
SELECT Name,
Phone,
Phone1,
Phone2,
[Phone Personal],
Fax,
Fax1,
[E-mail],
[E-mail1],
[E-mail2]
FROM t_comp
PIVOT (MAX(Value)
FOR Label IN (Phone,
Phone1,
Phone2,
[Phone Personal],
Fax,
Fax1,
[E-mail],
[E-mail1],
[E-mail2])) p
结果
Name Phone Phone1 Phone2 Phone Personal Fax Fax1 E-mail E-mail1 E-mail2
Expert Bike EU (541) 764-3011 (541) 754-3013 (541) 754-3014 1111 111 1111 +44 41 444-5555 +44 41 444-5595 NULL NULL NULL
Sport Playground (541) 754-3010 NULL NULL NULL NULL NULL office@ExpertBike.com John@sales.com Mary@purchasing.com