所以,我的问题是如何将变量url设置为yt之后的某个人类型?例如,!yt [youtbube link]生成url = [youtube link]
这是我目前的代码,感谢任何帮助,谢谢:)
@client.command(pass_context=True)
async def yt(ctx):
url = 'https://www.youtube.com/watch?v=rPOUewuNKFE'
author = ctx.message.author
voice_channel = author.voice_channel
vc = await client.join_voice_channel(voice_channel)
player = await vc.create_ytdl_player(url)
player.start()
答案 0 :(得分:1)
@client.command(pass_context=True)
async def yt(ctx, url):
author = ctx.message.author
voice_channel = author.voice_channel
vc = await client.join_voice_channel(voice_channel)
player = await vc.create_ytdl_player(url)
player.start()
如果你愿意,你也可以使用标准函数注释(async def yt(ctx, url: str):
)指定参数的类型,但它不会非常有用,因为默认情况下它们仍然是作为字符串传递的。< / p>
答案 1 :(得分:0)
我假设你已经知道这一点,但有一些机器人可以为你做到这一点。如果您不这样做,您可以从YouTube给它一个链接,并确保机器人在您的语音通道中。我不确定你是否试图让它在多个语音通道中播放不同的链接。我非常怀疑机器人可以在多个语音通道上播放不同的歌曲,因为它必须与你在语音通道中。
答案 2 :(得分:0)
angular.module('myapp').controller('FirstCont', function ($scope, $http) {
console.log("OUT");
$scope.slctd_lng = 'SDF'
$scope.slct_att = 'SD'
window.initAutocomplete = function () {
console.log("entered INIT");
$scope.autocomplete = new google.maps.places.Autocomplete((document.getElementById('autocomplete')),{ types: ['geocode'] });
$scope.autocomplete.addListener('place_changed', $scocpe.fillInAddress);
}
$scope.fillInAddress = function () {
var place = $scope.autocomplete.getPlace();
}
$scope.geolocate = function() {
if (navigator.geolocation) {
navigator.geolocation.getCurrentPosition(function (position) {
var geolocation = {
lat: position.coords.latitude,
lng: position.coords.longitude
};
var circle = new google.maps.Circle({
center: geolocation,
radius: position.coords.accuracy
});
$scope.autocomplete.setBounds(circle.getBounds());
});
}
}});