我是铁杆的新手,我没有使用设计。我的问题是,当我在我的表单中使用password_field作为我的密码而我只更新subscriber_number时,密码在我的数据库中变为空白。但是当我使用text_field作为我的密码时,可以看到并保存实际值。这就是我想要做的事情:
class EdiUser < ActiveRecord::Base
validates_presence_of :subscriber_number
validates_presence_of :password, :on => :create
end
并在我的控制器中:
def update
@trader_edi_user = TraderEdiUser.find(params[:id])
@edi_user = EdiUser.find(@trader_edi_user.edi_user_id)
#@edi_user.update_attributes(edi_user_params)
if params[:edi_user][:password].blank? == true
@edi_user.update_attributes(edi_user_subscriber_number)
else
@edi_user.update_attributes(edi_user_params)
end
redirect_to :back
end
private
def edi_user_params
params.require(:edi_user).permit(:id, :subscriber_number, :password, :password_confirmation)
end
def edi_user_subscriber_number
params.require(:edi_user).permit(:subscriber_number)
end
这是我的表格:
<%= form_for(@edi_user, url: {controller: 'maintenance/edi_users', action: 'update'}, html: {class: "form-horizontal", id: "edit_edi"}) do |f| %>
<div class="form-group edi subs">
<label class="col-sm-3 control-label has-feedback">Subscriber Number</label>
<div class="col-sm-9">
<%= f.text_field :subscriber_number, :class => "form-control req", :required => 'true', :id => "subscriber" %>
<br>
</div>
</div>
<div class="form-group edi pass">
<label class="col-sm-3 control-label has-feedback">Password</label>
<div class="col-sm-9">
<%#= f.text_field :password, :class => "form-control", :id => "password", :minlength => 6 %>
<%= f.password_field :password, :class => "form-control", :id => "password" %>
<br>
</div>
</div>
<div class="form-group edi confirm_pass">
<label class="col-sm-3 control-label has-feedback">Confirm Password</label>
<div class="col-sm-9">
<%= f.password_field :password_confirmation, :class => "form-control", :id => "confirm_password", data: { :match => "#password"} %>
<br>
</div>
</div>
<div class="row">
<div class="col-sm-12">
<div class="pull-right">
<%= button_tag type: "submit", class: "btn btn-md btn-success raised pull-right", id: "update_btn2" do %>
<i class="fa fa-check" aria-hidden="true"></i> <%= t('Button.Update') %>
<% end %>
</div>
</div>
</div>
<% end %>
我的控制器上的更新操作的代码错了吗?还是有什么我想念的?
非常感谢你
答案 0 :(得分:0)
你可以拒绝空白参数,
def update
@trader_edi_user = TraderEdiUser.find(params[:id])
@edi_user = EdiUser.find(@trader_edi_user.edi_user_id)
edi_user_params.reject! {|k, v| v.blank?}
if @edi_user.update_attributes(edi_user_params)
# Success
else
# Error
end
redirect_to :back
end
private
def edi_user_params
params.require(:edi_user).permit(:id, :subscriber_number, :password, :password_confirmation)
end
出于安全原因,我仍然建议您使用Devise之类的东西。
答案 1 :(得分:0)
在方法的第一行添加以下行可能会解决您的问题
redirect_to password_blank_path if edi_user_params[:password].blank?
但是,这里有一些针对您的代码的建议
@trader_edi_user = TraderEdiUser.find(params[:id])
@edi_user = EdiUser.find(@trader_edi_user.edi_user_id)
@edi_user.update_attributes(edi_user_params)
在使用之前允许使用params
建议使用两个模型之间的关系
使用find_by而不是find,如果找不到任何内容,则导致查找可能引发异常
# assuming TraderEdiUser belongs_to :edi_user
@trader_edi_user = TraderEdiUser.find_by(id: edi_user_params[:id])
@trader_edi_user.edi_user.update_attributes(edi_user_params) if @trader_edi_user.present?
答案 2 :(得分:0)
我认为你正在寻找这个:
# edi_user.rb
validates :password, presence: true, if: :should_validate?
def should_validate?
new_record? # other condition you could put here
end
关于你的控制器如何:
def update
@trader_edi_user = TraderEdiUser.find(params[:id])
@edi_user = EdiUser.find(@trader_edi_user.edi_user_id)
if @edi_user.update(edi_user_params)
redirect_to some_where_path
else
redirect_to elsewhere_path
end
end
private
def edi_user_params
params.require(:edi_user).permit(:id, :subscriber_number, :password, :password_confirmation)
end