PHP接收JSON POST数据

时间:2017-08-16 02:48:11

标签: php json api

我正在尝试从外部系统接收JSON数据,然后处理并保存到我的本地数据库。当事件触发时,外部系统会将以下数据发送到我的系统。

外部系统日志显示:

Log 1:   Date/Time: 16 August 2017 11:54:44 AM
Status: Failure
Server: Apache https://blahblah.com/abc/data.php
Status Code:    OK
Event Content:  [{"field":"_USERNAME","value":""},
{"field":"_PASSWORD","value":""},
{"field":"_TOKEN","value":""},
{"field":"_CODE","value":"L77H4XD6ZA"},
{"field":"_SUBMITTEDDATE","value":"2017.08.16.01.54"},
{"field":"_SUBMITTEDDATEEXT","value":"2017.08.16.01.54.39.610"},
{"field":"_EDITEDDATE","value":"2017.08.16.01.55"},
{"field":"_SEQUENTIALID","value":"39a1cad9-2582-e711-9477-06c7814985cc"},
{"field":"_COMPLETETYPE","value":"Complete"},
{"field":"_LANGUAGE","value":"en"},
{"field":"_TOTALTIME","value":"12.59"},{"field":"_LINKURL","value":"http%3a%2f%2fsurv.blah.com%2ftest3%3fusr%3dL77H4XD6ZA"},
{"field":"GENDER","value":"TEXT%3aFemale%3bVALUE%3a2"},
{"field":"AGE","value":"TEXT%3a40%2b-%2b44%3bVALUE%3a6"},
{"field":"STATE","value":"TEXT%3aVIC%3bVALUE%3a2"},
{"field":"END_CHC","value":"TEXT%3aComplete%3bVALUE%3a2"},
{"field":"D2H","value":""},
{"field":"D2V","value":""},
{"field":"PCODE","value":""},
{"field":"PSTATE","value":""},
{"field":"PREGION","value":""},
{"field":"STATEREGION","value":""},
{"field":"TEST1","value":""}]

所以,在我的php文件(https://blahblah.com/abc/data.php)中,我有

$json = file_get_contents('php://input');
$obj = json_decode($json);

我一直在尝试使用foreach()循环来尝试获取每个字段和值,然后放入数据库,如

foreach($obj as $key => $value)
{
    $qry = $conn->prepare('INSERT INTO `key_value`(`db_id`, `rkey`, `rvalue`) VALUES (NULL,$key,$value)');
    $qry->execute();
}

但它不起作用,我或者得到关于foreach循环的错误,或者如果我只使用echoing或var_dumping,当我使用Postman或ARC Chrome API测试时,我在响应中得到NULL的应用程序。

所以,我怀疑我对如何做到完全错误。

任何人都可以帮助指导我吗?

编辑:我看过Receive JSON POST with PHP和其他一些人,但工作答案并不清楚。

1 个答案:

答案 0 :(得分:1)

你在这里遇到了一些问题。首先,您需要将true作为第二个参数传递给json_decode,以便获取关联数组而不是stdClass。然后,当您迭代结果时,您不需要$ key,$ value是结果数组中的每个条目(每个“行”)。尝试运行它来查看正在发生的事情:

@IBInspectable

另外一些结果是url编码的,所以你可能想要在持久化之前解码它。