Question

我很可能因为缺乏经验而面临问题。

我从MYSQL DATABASE成功获取数据，并成功填充了第二个DROPDOWN菜单。

问题是......当我点击＆＃34;验证＆＃34;提交并记录变量中的数据，它清除选择的上一个选项。我无法在变量中记录所选选项。

<?php
$location = "";
$locationf = "";
$system = "";
$systemf = "";

$conn = mysqli_connect('localhost', 'root', 'test', 'SRSBASE')
        or die('Cannot connect to db');

$result = $conn->query("select distinct SUB_ACCOUNT from SRSLOAD");

if (isset($_POST["selec"]["account"])) {
    $location = $_POST["selec"]["account"];
    $locationf = $location;
    $locationf = sprintf('%s', $locationf);
}

echo "Location: $locationf";

$conn2 = mysqli_connect('localhost', 'root', 'test', 'SRSBASE')
        or die('Cannot connect to db');

$result2 = $conn2->query("select distinct SYSTEMNAME from SRSLOAD where SUB_ACCOUNT='$locationf'");

if (isset($_POST["selec"]["system"])) {
    $system = $_POST["selec"]["system"];
    $systemf = $system;
}

echo "System: $systemf";

$post_at = "";
$post_at_to_date = "";
$post_at_todate = "";

$queryCondition = "";
if (!empty($_POST["search"]["post_at"])) {
    $post_at = $_POST["search"]["post_at"];
    list($fiy, $fim, $fid) = explode("-", $post_at);

    $post_at_todate = date('YY-mm-dd');
    if (!empty($_POST["search"]["post_at_to_date"])) {
        $post_at_to_date = $_POST["search"]["post_at_to_date"];
        list($tiy, $tim, $tid) = explode("-", $_POST["search"]["post_at_to_date"]);
        $post_at_todate = "$tiy-$tim-$tid";

    //TESTING SELECTED TARGETS
    //echo $post_at;
    //echo "/";
    //echo $post_at_todate;
    }

    //$queryCondition .= "WHERE RDATE BETWEEN '$fiy-$fim-$fid' AND '" . $post_at_todate . "'";
    $queryCondition .= "WHERE RDATE BETWEEN '$post_at' AND '" . $post_at_todate . "'";
}

//$sql = "SELECT * from SRSLOAD " . $queryCondition . " ORDER BY post_at desc";
//$sql = "select * from SRSLOAD where rdate between '$post_at' AND $post_at_todate;"

$sql = sprintf("SELECT * FROM SRSLOAD WHERE RDATE BETWEEN '%s' AND '%s' AND SYSTEMNAME='%s' AND SUB_ACCOUNT='%s'", $post_at, $post_at_todate, $systemf, $locationf);

$result3 = mysqli_query($conn, $sql);
?>
<!DOCTYPE html>
<html>
    <head>
        <title>Storage Report System - Search</title>
        <script src="jquery-1.9.1.js"></script>
        <link rel="stylesheet" href="jquery-ui-1.11.4.css">

        <style>
            .table-content{border-top:#CCCCCC 4px solid; width:50%;}
            .table-content th {padding:5px 20px; background: #F0F0F0;vertical-align:top;}
            .table-content td {padding:5px 20px; border-bottom: #F0F0F0 1px solid;vertical-align:top;}
        </style>
    </head>
    <body>

        <h2 style='font-family:arial'>Storage Report System - Search</h2>

        <form name='sname' id='sname' action='' method='POST'>
            <select id='select' name="selec[account]" value="<?php echo $location; ?>" >
                <option value='-1'>--Select the Location--</option>

                <?php
                while ($row = $result->fetch_assoc()) {
                    unset($sub_acc);
                    $sub_acc = $row['SUB_ACCOUNT'];
                    echo '<option value="' . $sub_acc . '">' . $sub_acc . '</option>';
                }
                ?>

            </select>
            <input type='submit' value='Validate' />
        </form>

        <form name='sname' id='sname' action='' method='POST' >
            <select id='system' name="selec[system]" value="<?php echo $system; ?>" >

                <option value='-1'>--Select the System--</option>
                <?php
                while ($row2 = $result2->fetch_assoc()) {

                    unset($syst);
                    $syst = $row2['SYSTEMNAME'];
                    echo '<option value="' . $syst . '">' . $syst . '</option>';
                }
                ?>
            </select>
            <input type='submit' value='Validate' />
        </form>

        <div class="demo-content">
            <form name="frmSearch" method="post" action="">
                <p class="search_input">
                    <input type="text" placeholder="From Date" id="post_at" name="search[post_at]" value="<?php echo $post_at; ?>" class="input-control" />
                    <input type="text" placeholder="To Date" id="post_at_to_date" name="search[post_at_to_date]" style="margin-left:10px" value="<?php echo $post_at_to_date; ?>" class="input-control" />
                    <input type="submit" name="go" value="Search" >
                </p>
                <?php if (!empty($result3)) { ?>
                    <table class="table-content">
                        <thead>
                            <tr>
                                <th width="30%"><span>SYSTEM NAME</span></th>
                                <th width="50%"><span>DATE</span></th>
                                <th width="20%"><span>HSM</span></th>
                            </tr>
                        </thead>
                        <tbody>
                            <?php
                            while ($row3 = mysqli_fetch_array($result3)) {
                                ?>
                                <tr>
                                    <td><?php echo $row["SYSTEMNAME"]; ?></td>
                                    <td><?php echo $row["RDATE"]; ?></td>
                                    <td><?php echo $row["HSM_MCDS"]; ?></td>

                                </tr>
                                <?php
                            }
                            ?>
                        <tbody>
                    </table>
                <?php } ?>
            </form>
        </div>
        <script src="jquery-ui-1.10.3.js"></script>
        <script>
            $.datepicker.setDefaults({
                showOn: "button",
                buttonImage: "datepicker.png",
                buttonText: "Date Picker",
                buttonImageOnly: true,
                dateFormat: 'yy-mm-dd'
            });
            $(function () {
                $("#post_at").datepicker();
                $("#post_at_to_date").datepicker();
            });
        </script>
    </body>
</html>

Answer 1

因为你有两种形式。每个表单都有自己的选择和提交。单击“提交”时，仅发送带有“选择”的相应表单。如果要从两个选择中获取数据，则必须同时选择一个表单并提交一个。类似这样的代码：

<form name='sname' id='sname' action='' method='POST'>
    <select id='select' name="selec[account]" value="<?php echo $location; ?>" >
        <option value='-1'>--Select the Location--</option>
        <?php
        while ($row = $result->fetch_assoc()) {
            unset($sub_acc);
            $sub_acc = $row['SUB_ACCOUNT'];
            echo '<option value="' . $sub_acc . '">' . $sub_acc . '</option>';
        }
        ?>
    </select>

    <select id='system' name="selec[system]" value="<?php echo $system; ?>" >
        <option value='-1'>--Select the System--</option>
        <?php
        while ($row2 = $result2->fetch_assoc()) {
            unset($syst);
            $syst = $row2['SYSTEMNAME'];
            echo '<option value="' . $syst . '">' . $syst . '</option>';
        }
        ?>
    </select>
    <input type='submit' value='Validate' />
</form>

问题制作搜索页面PHP和MYSQL

1 个答案: