time1 = '2016-01-01'
timelen = A vector of time lengths in hours
time1_vec = ymd(time1) + dhours(timelen)
我正在获得Y-M-D，但这些是每小时的时间步长，我想在time1_vec中获得"2016-01-01 01:00:00 UTC", "2016-01-01 02:00:00 UTC"等。
我该怎么做？
这对我有用：
ymd(time1) + dhours(2)
[1] "2016-01-01 02:00:00 UTC"
structure(c(0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14,
15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30,
31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46,
47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62,
63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78,
79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94,
95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107, 108,
109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120, 121,
122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133, 134,
135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146, 147,
148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159, 160,
161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172, 173,
174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184, 185, 186,
187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198, 199,
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211, 212,
213, 214, 215, 216, 217, 218, 219, 220, 221, 222, 223, 224, 225,
226, 227, 228, 229, 230, 231, 232, 233, 234, 235, 236, 237, 238,
239), .Dim = 240L)
这就是我得到的：
time1_vec
[1] "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01"
[7] "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01"
[13] "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01"
[19] "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01" "2016-01-01"
[25] "2016-01-02" "2016-01-02" "2016-01-02" "2016-01-02" "2016-01-02" "2016-01-02"
等
答案 0 :(得分：0)
您可以seq.POSIXt使用lubridate仅ymd_hm：
library(lubridate)
seq.POSIXt(from=ymd_hm('2016-01-01 00:00'), by="1 hour", length=24)
[1] "2016-01-01 00:00:00 UTC" "2016-01-01 01:00:00 UTC" "2016-01-01 02:00:00 UTC" "2016-01-01 03:00:00 UTC"
[5] "2016-01-01 04:00:00 UTC" "2016-01-01 05:00:00 UTC" "2016-01-01 06:00:00 UTC" "2016-01-01 07:00:00 UTC"
[9] "2016-01-01 08:00:00 UTC" "2016-01-01 09:00:00 UTC" "2016-01-01 10:00:00 UTC" "2016-01-01 11:00:00 UTC"
[13] "2016-01-01 12:00:00 UTC" "2016-01-01 13:00:00 UTC" "2016-01-01 14:00:00 UTC" "2016-01-01 15:00:00 UTC"
[17] "2016-01-01 16:00:00 UTC" "2016-01-01 17:00:00 UTC" "2016-01-01 18:00:00 UTC" "2016-01-01 19:00:00 UTC"
[21] "2016-01-01 20:00:00 UTC" "2016-01-01 21:00:00 UTC" "2016-01-01 22:00:00 UTC" "2016-01-01 23:00:00 UTC"
答案 1 :(得分：0)
尝试ymd_hms：
time1 = "2016-01-01:00:00:00"
time1_vec = ymd_hms(time1) + dhours(timelen)